The sum of the angle measures of any trapezoid is greater than the sum of the angle measures of any parallelogram.

Answers

Answer 1

Answer:

Answer:

False. Trapezoids and parallelograms are both types of quadrilaterals. 4 sided figures. The sum of a quadrilateral's angles is always equal to 360. The sum of a trapezoid's angles, as well as the sum of a parallelogram's angles, will always be equal. I hope this answers your question.

Step-by-step explanation:

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A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B: 4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answers

This question is not complete, I got the complete one from google as below:

The summary statistics are as follows.

Type A Type B

x1 = 76.3 hrs x2 = 65.1 hrs

s1 = 4.5 hrs s2 = 5.1 hrs

n1 = 11 n2 = 9

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs

What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answer:

Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Step-by-step explanation:

The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.

Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

3+ 6 x{( 15 +9)=3-2}. Rajah got 49 while Obet got 39. Whose answer was correct? Prove your answer.asap i need it pls i need solution

Answers

Answer:

39, Obet is right

Step-by-step explanation:

I guess the = should be ÷ or else it doesn't make sense.

Simplify in steps considering the hierarchy of operations:

3 + 6 × {(15 + 9) ÷ 3 - 2} = Parenthesis
3 + 6 × {24 ÷ 3 - 2} = Parenthesis, division
3 + 6 × {8 - 2} = Parenthesis, subtraction
3 + 6 × 6 = Multiplication
3 + 36 = Addition
39

Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept form)

Answers

Answer:

$\displaystyle y=-(1)/(2)x+4$

Step-by-step explanation:

Equation of a Line

We can find the equation of a line by using two sets of data. It can be a pair of ordered pairs, or the slope and a point, or the slope and the y-intercept, or many other combinations of appropriate data.

We are given a line

$y - 12 = 2x -8$

And are required to find a line perpendicular to that line. Let's find the slope of the given line. Solving for y

$y = 2x +4$

The coefficient of the x is the slope

$m=2$

The slope of the perpendicular line is the negative reciprocal of m, thus

$\displaystyle m'=-(1)/(2)$

We know the second line passes through (2,3). That is enough information to find the second equation:

$y-y_o=m'(x-x_o)$

$\displaystyle y-3=-(1)/(2)(x-2)$

Operating

$\displaystyle y=-(1)/(2)(x-2)+3$

Simplifying

$\displaystyle y=-(1)/(2)x+4$

That is the equation in slope-intercept form. Intercept: y=4

What is the value of (–7 + 3i) + (2 – 6i)? a. –9 – 3i
b. –9 + 9i
c. –5 + 9i
d. –5 – 3i

Answers

Answer:

Step-by-step explanation:

(-7 + 3i) + (2-6i)

=-7 + 3i + 2 -6i

=(-7+2) + (3i -6i)

=-5 -3i

Answer:

(-7+3I)+(2-6I)

= -7+3i+2-6i

= -5-3I

so answer is d ie -5-3i

Consider the following hypothesis test:H 0: = 17H a: 17A sample of 40 provided a sample mean of 14.12. The population standard deviation is 4.a. Compute the value of the test statistic (to 2 decimals). (If answer is negative, use minus "-" sign.)b. What is the p-value (to 4 decimals)?c. Using = .05, can it be concluded that the population mean is not equal to 17? SelectYesNoItem 3Answer the next three questions using the critical value approach.d. Using = .05, what are the critical values for the test statistic (to 2 decimals)? ±e. State the rejection rule: Reject H 0 if z is Selectgreater than or equal togreater thanless than or equal toless thanequal tonot equal toItem 5 the lower critical value and is Selectgreater than or equal togreater thanless than or equal toless thanequal tonot equal toItem 6 the upper critical value.f. Can it be concluded that the population mean is not equal to 17?

Answers

Answer:

We conclude that the population mean is not equal to 17.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 17

Sample mean, $\bar{x}$ = 14.12

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 4

First, we design the null and the alternate hypothesis

$H_(0): \mu = 17\nH_A: \mu \neq 17$

We use Two-tailed z test to perform this hypothesis.

a) Formula:

$z_(stat) = \displaystyle\frac{\bar{x} - \mu}{(\sigma)/(√(n)) }$

Putting all the values, we have

$z_(stat) = \displaystyle(14.12 - 17)/((4)/(√(40)) ) = -4.5536$

b) P-value can be calculated from the standard z-table.

P-value = 0.0000

c) Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17

d) Now, $z_(critical) \text{ at 0.05 level of significance } = \pm 1.96$

e) Rejection Rule:

We reject the null hypothesis if it is less than lower critical value and greater than the upper critical value

If the z-statistic lies outside the acceptance region which is from -1.96 to +1.96, we reject the null hypothesis.

f) Since the calculated z-stat lies outside the acceptance region, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17.

Final answer:

The test statistic is -1.78 and the p-value is 0.0761, indicating that we fail to reject the null hypothesis. Therefore, it cannot be concluded that the population mean is not equal to 17.

Explanation:

The test statistic can be calculated using the formula:

test statistic = (sample mean - population mean) / (population standard deviation / sqrt(sample size))

Plugging in the given values, we get:

test statistic = (14.12 - 17) / (4 / sqrt(40))

Calculating this gives us a test statistic value of -1.78.

The p-value can be calculated using the test statistic. We need to find the probability that a test statistic at least as extreme as -1.78 would occur assuming the null hypothesis is true. Using a standard normal distribution table or software, we find the p-value to be approximately 0.0761.

Since the p-value is greater than the significance level (alpha = 0.05), we fail to reject the null hypothesis. Therefore, we can conclude that there is not enough evidence to suggest that the population mean is not equal to 17.

Learn more about Hypothesis testing here:

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A quadrilateral has angles that measure 44°, 89°, and 127°. What is the measure of the fourth angle?

Answers

The sum of angles in a quadrilateral = 360 degrees.

Let the fourth angle be x:

Therefore: 44 + 89 + 127 + x = 360

260 + x = 360

x = 360 - 260

x = 100

x = 100°

I hope this helps.

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