How many blocks will Colin run by the end of the sixth week?
A.
Use objects to model the problem.
Put out 1 chip to represent the blocks run in week one. Put out twice that amount for week two. Put out twice that amount (from week two) for week three. Do this 3 more times, putting out twice the amount from the previous week each time.
B.
Make a table.
In the first row, write first week - 2 blocks. In the next row, write second week - 4 blocks. In the third row, write third week -6 blocks. Continue this pattern for three more rows.
C.
Write a number sentence.
(1 + 2) × 6 = x
Add the number of blocks run in the first and 2nd week. Then multiply the sum by the number of weeks (6).
Answer:
119 is the answer
Step-by-step explanation:
My teacher explained this question and we got 199 as the answer
Statements A, B, and C are true.
Step-by-step explanation:
Step 1:
A cone, a cylinder and a sphere all have radii of 3 inches. The cone and cylinder have heights of 2 inches.
The volume of the cone, Here r = 3 inches and h = 2 inches.
So the volume of the cone cubic inches.
The volume of the cylinder, Here r = 3 inches and h = 2 inches.
So the volume of the cylinder = cubic inches.
The volume of the sphere, Here r = 3 inches.
So the volume of the sphere cubic inches.
Step 2:
Now we check to see which statements are true.
A. About 113 cubic inches of catnip will fit inside a sphere-shaped toy so it is true.
B. About 18.8 cubic inches of catnip will fit inside a cone-shaped toy so it true.
C. The sphere-shaped toy holds the most of the three so it is true.
D. No shape holds 169.6 cubic inches, so D is false.
E. The toys shaped like a cone and a cylinder do not hold the same amount of catnip in them. So it is false.
P.S. I couldn't see the options B, D, and E completely.
Answer:
This is because even when the quality of the variable x is 0, the value of b still exists and is the starting point for y.
Step-by-step explanation:
To prove this, we start with the base form of the equation and input 0 for x.
y = mx + b
y = m(0) + b
y = 0 + b
y = b