36 is 0.09% of what number

Answers

Answer 1
Answer: х-100%
36-0,06%
x=(36*100)\0,06=60000
Answer:60000

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The width (W) of a rectangular garden is 7 feet longer than the length (L). The area of the garden is 30 square feet

Answers

Well you have to remember that area is length times width. So 4.285714286 Or since most gardens are shaped like a square. You would have to 7×7+7×(number above) to get the answer. Hope that helps

When x=3 and y=5 by how much does the value of 3x^2-2y exceed the value of 2x^2-3/

Answers

x = 3

y = 5

3x^2 – 2y

= 3(3)^2 - 2(5)

=> 3(9) - 10 = 17

And 2x^2– 3y

=> 2(3)^2 - 3(5)

=> 2(9) - 15 = 3

17 - 3 = 14

This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14

14 is the correct answer.

When you use x = 3 and

 
y = 5 in the given expressions, 3x2 – 2y = 3(3)2– 2(5) = 27 – 10 = 17 and

2x2 – 3y = 2(3)2 – 3(5) = 18 – 15 = 3.

Then subtract 3 from 17....17-3 = 14.

14 is your answer.

Hope I helped ;]

I will upvoteWhat is the 12th term in the sequence?

Note: Use the explicit rule.

a_n=−16+2n

Enter your answer in the box.
a_12=

Answers

easy, sub 12 for n
a12=-16+2(12)
a12=-16+24
a12=8

What does -1-6x-6>-11-7x equal

Answers

Hey there, first, we simplify -6x-7>-7x-11, second, add 7x to both sides, -6x-7+7x>-7x-11+7x=x-7>-11, third, add 7 to both sides, x-7+7>-11+7=x>-4. Therefore, the answer is x>-4

Find the product of a number p to the fourth power and the same number to the fifthpower____

Answers

The product of a number p to the fourth power (p⁴) and the same number to the fifth power (p⁵) can be found by multiplying them together.

(p⁴) * (p⁵) = p^(4+5) = p⁹

Therefore, the product of a number p to the fourth power and the same number to the fifth power is p⁹.  

Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will last 10 years. The rules of the competition are simple. Each child can split up his or her $2000 into as many separate investments as they please. The children are encouraged to do their research on types of investments. The initial investments made may not be changed at any point during the 10 years; no money may be added and no money may be moved. Whichever child has made the most money after 10 years will be awarded an additional $10,000. Child Performance of investments over the course of the competition Albert $1000 earned 1.2% annual interest compounded monthly $500 lost 2% over the course of the 10 years $500 grew compounded continuously at rate of 0.8% annually Marie $1500 earned 1.4% annual interest compounded quarterly $500 gained 4% over the course of 10 years Hans $2000 grew compounded continuously at rate of 0.9% annually Max $1000 decreased in value exponentially at a rate of 0.5% annually $1000 earned 1.8% annual interest compounded biannually (twice a year) 1. What is the balance of Albert’s $2000 after 10 years? 2. What is the balance of Marie’s $2000 after 10 years? 3. What is the balance of Hans’ $2000 after 10 years? 4. What is the balance of Max’s $2000 after 10 years? 5. Who is $10,000 richer at the end of the competition?

Answers

The balance of Albert is $2159.07; the balance of Marie is $2244.99, the balance of Hans is $2188.35, and the balance of Max is $2147.40. Marie is $10,000 richer at the end of the competition.

What is Compound interest?

Compound interest is defined as interest paid on the original principal and the interest earned on the interest of the principal.

To determine the balance of Albert’s $2000 after 10 years :

If the amount of $1000 at 1.2 % compounded monthly,

A = P(1 +r/n)ⁿ n = 10 years

here P = $1000 and r = 1.2

A = 1000(1 + 0.001)¹²⁰

A = $1127.43

If Albert $500 losing 2%

So 0.98 × 500 = $490

If $500 compounded continuously at 0.8%

So A = Pe^(rt)

A = 500e^(0.008* 10)

A = 541.6

So the balance of Albert’s $2000 after 10 years :

Total balance = 1127.43 + 490.00+ 541.64 = $2159.07

To determine the balance of Marie’s $2000 after 10 years:

If 1500 at 1.4 % compounded quarterly,

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

If $500 Marie’s gaining 4 %

So 1.04 × 500 = $520.00

So the balance of Marie’s $2000 after 10 years

Total balance = 1724.99 + 520.00 = $2244.99

To determine the balance of Hans’ $2000 after 10 years:

If $2000 compounded continuously at 0.9%

So A = 2000e^(0.009* 10)

A = $2188.3

To determine the balance of Max’s $2000 after 10 years :

If $1000 decreasing exponentially at 0.5 % annually

So A = 1000(1 - 0.005)¹⁰= $951.11

If $1000 at 1.8 % compounded bi-annually

So A = 1000(1 + 0.009)²⁰ = $1196.29

So the balance of Max’s $2000 after 10 years

Total balance = 951.11 + 1196.29 = $2147.40

Therefore, Marie is $10,000 richer at the end of the competition.

Learn more about Compound interest here :

brainly.com/question/25857212

#SPJ2

Answer:

Step-by-step explanation:

Albert:

$1000 earned 1.2% annual interest compounded monthly

= 1000 (1+.001)120

(periodic interest = .012/12 ,n is periods = 10yr x 12 mos)

$500 lost 2% over the course of the 10 years

= 500 (.98)

$500 grew compounded continuously at rate of 0.8% annually

= 500 e^008(10) 10 years interest .008 (in decimal form)

Add these three to see how Albert did with his investments