CIO4-=-1
CI=4O=-1
O has a 2- oxidation change so
CI+4(-2)=-1
CI+(-8)=-1
CI=-1+8=7
So the oxidation number of chlorine is 7 in this case
(2) C6H12O6 (4) CH3COOH
Answer: Option (4) is the correct answer.
Explanation:
Substance which are able to conduct electricity are ionic in nature. This means that only ionic substances can conduct electricity because they dissociate into ions.
Therefore, out of the given options only acetic acid is ionic in nature.
Though is a weak acid but it does dissociate into ions and hence, it forms a solution that conducts an electric current.
Sawing a board in half is a physical change not a chemical change the board doesnt change wood or whatever material it is is still would still be wood
If it were burned it would be a chemical change but its properties stay the same atomically so thats why its not a chemical change.
The current in a circuit is governed by voltage and resistance, as dictated by Ohm's Law. The voltage-current relationship can be linear in ohmic materials or nonlinear in non-ohmic materials.
The current flowing in a circuit depends primarily on two variables: voltage and resistance. This relationship is defined through Ohm's Law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R), or I=V/R.
When the voltage increases while the resistance remains constant, the current will increase. Conversely, when the resistance increases while the voltage remains constant, the current will decrease. Thus, for example, if the resistance doubles, the current is cut in half.
However, it is important to note that not all materials follow this linear relationship. Some materials, known as ohmic materials, follow Ohm's Law, while others, known as non-ohmic materials, exhibit a nonlinear voltage-current relationship.
#SPJ12
b. 0.571
c. 0.569
d. 0.537
e. 0.214
Answer:
The concentration of CaCl2 in this solution is 0.564 molar (option A)
Explanation:
Step 1: Data given
Mass of CaCl2 = 23.7 grams
Mass of water = 375 grams
Density of solution is 1.05 g/mL
Step 2: Calculate total mass
Total mass = mass of CaCl2 + mass of water
Total mass = 23.7 grams + 375 grams = 398.7 grams
Step 3: Calculate volume of the solution
Density = mass / volume
Volume = mass / density
Volume = 398.7 grams / 1.05 g/mL
Volume = 379.7 mL = 0.3797 L
Step 4: Calculate moles CaCl2
Moles CaCl2 = mass CaCl2 / molar mass CaCl2
Moles CaCl2 = 23.7 grams / 110.98 g/mol
Moles CaCl2 = 0.214 moles
Step 5: Calculate concentration
Concentration of CaCl2 = moles / volume
Concentration of CaCl2 = 0.214 moles / 0.3797 L
Concentration of CaCl2 = 0.564 mol / L = 0.564 molar
The concentration of CaCl2 in this solution is 0.564 molar (option A)