Train A arrives at central station on the hour and every 12 minutes. Train B arrives on the hour and every 15 minutes. When do both trains arrive at thesame time?

A) On the hour and 30 minutes past the hour
B) On the hour and 15 minutes to the hour
C) On the hour and 27 minutes past the hour
D) On the hour

Please explain why you chose the answer and how you achieved it

Answers

Answer 1

Answer: 2________24___________30
3________36___________45
4________48___________60
5________60, found common minute count.

60 minutes.__________A____________B
__________0____________0
1________12___________15

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If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.

Answers

$2 √(17-x) =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \geq 5\n\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=<5;\ 17>\n\n2 √(17-x) =2(x-5)\ /:2\n\n √(17-x) =x-5\ \ \ \Rightarrow\ \ \ (√(17-x))^2 =(x-5)^2\n\n17-x=x^2-10x+25\n\n$

$x^2-9x+18=0\n\n x^2-3x-6x+18=0\n\nx(x-3)-6(x-3)=0\n\n(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\n\nx=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \ (x)/(4) = (6)/(4) =1.5\n\nAns.\ (x)/(4) =1.5$

140% of what is 56? My profile says I'm 19 but I'm really not.

Answers

$Whole * percent = part\n x * 1.40 = 56\n x = (56)/(1.4)=40$

x = 40

PLEASEEE HELPP The water usage at a car wash is modeled by the equation W(x) = 3x3 + 4x2 − 18x + 4, where W is the amount of water in cubic feet and x is the number of hours the car wash is open. The owners of the car wash want to cut back their water usage during a drought and decide to close the car wash early two days a week. The amount of decrease in water used is modeled by D(x) = x3 + 2x2 + 15, where D is the amount of water in cubic feet and x is time in hours. Write a function, C(x), to model the water used by the car wash on a shorter day. C(x) = 2x3 + 2x2 − 18x − 11
C(x) = 3x3 + 2x2 − 18x + 11
C(x) = 3x3 + 2x2 − 18x − 11
C(x) = 2x3 + 2x2 − 18x + 11

Answers

We have been given that the water usage at a car wash is modeled by the equation $W(x) = 3x^3+4x^2-18x + 4$ , where W is the amount of water in cubic feet and x is the number of hours the car wash is open.

The amount of decrease in water used is modeled by $D(x) = x^3 + 2x^2 + 15$ , where D is the amount of water in cubic feet and x is time in hours.

The function C(x) will be difference of W(x) and D(x) that is $C(x)=W(x)-D(x)$ .

Upon substituting both function values in above formula, we will get:

$C(x)=3x^3+4x^2-18x + 4-(x^3 + 2x^2 + 15)$

Let us remove parenthesis.

$C(x)=3x^3+4x^2-18x + 4-x^3-2x^2-15$

Combine like terms.

$C(x)=3x^3-x^3+4x^2-2x^2-18x+4-15$

$C(x)=2x^3+2x^2-18x-11$

Therefore, the function $C(x)=2x^3+2x^2-18x-11$ represents the water used by the car wash on a shorter day and option A is the correct choice.

Answer:

Step-by-step explanation:

An angle measures 47°. What are the measures of the angle’s complement and supplement?

Answers

we know that

Two angles are supplementary if the sum of their angles is equal to 180 degrees

and

Two angles are complementary if the sum of their angles equals 90 degrees

if an angle measures $47$ °

then

Angle Supplementary= $180-47$

Angle Supplementary= $133$ °

Angle Complementary= $90-47$

Angle Complementary= $43$ °

Complementary equal 90 degrees.
90-47=43 degrees
Supplementary equal 180 degrees.
180-47=133 degrees

A

divide 18 cups if flour into two groups so the ratio is 4 to 5

Answers

Let us divide the flour into two groups, A and B
now we know from the given question
A/B = 4/5
A = 4B/5
We also know there are 18 cups of flour in total.
A + B = 18
So
(4B/5) + B = 18
(4B/5) + (5B/5) = 18
9B/5 = 18
B = (18*5)/9
   = 10
Then
A = 18 - B
   = 18 - 10
   = 8
So the ratio of dividing the 18 cups is 8:10

Match each expression to the correct verbal description.