If you were teaching a foreign visitor about checking and savings accounts at banks and credit unions in the USA, which item below would you say consumers of these accounts usually do not have as a protection of their rights?a.
Government-backed insurance on the deposits.
b.
Regulation of bank practices by government agencies.
c.
A written statement providing the current fees and policies for the account.
d.
No automatic fees charged to the account.

Answers

Answer 1

Answer: Answer: D. No automatic fees charged to the account.

If I had the chance to teach a foreigner regarding checking and savings account at the banks in the United States, I would remind him/her of this important note. There are no automatic fees charged to the account therefore, consumers cannot protect their rights.

Answer 2

Answer:

Answer:

d. No automatic fees charged to the account.

Step-by-step explanation:

The consumers of checking and savings accounts at banks and credit unions usually do not have the right when they are asked if they want automatic fee to be deducted or not. The banks themselves auto deduct the fee for some service provided like ATM cards issued to customers etc.

The correct answer is option D.

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A test has multiple choice questions with 5 choices for each answer; only one answer is correct for each question. Suppose a student guesses the answer to each question. Assuming the guesses are independent, find the probability that the student will not guess correctly on any one question.

What is the value of 5 over 6 divided by 3 over 4

Answers

Answer:

10/9

Step-by-step explanation:

5/6 ÷ 3/4 =
5/6 × 4/3 =
20/18 =
10/9

Is 21,28,35 a right triangle?

I will mark the CORRECT answer Brainiest.

Answers

Answer:

Yes

Step-by-step explanation:

If the sides match Pythagoras' Theorem, the triangle is a right triangle.

$21^(2) +28^(2)$

= $441+784$

= $1225$

= $35^(2)$

Answer:

Yes

Step-by-step explanation:

Criteria for finding a right triangle is that sum of square of two sides = square of the third side.

Let the sides be A, B and C.

( i.e )

A² + B² = C²

So,

Let,

A = 21

B = 28

C = 35

21² + 28² = 35²

441 + 784 = 1225

1225 = 1225

Hence,

Sides 21, 28, and 35 will form a right triangle.

Make x the subject of the formula $r = \sqrt{ (ax - p)/(q + bx) }$

Answers

Answer:

$\boxed{x = \frac{p + q {r}^(2) }{a - b {r}^(2) } }$

Step-by-step explanation:

$Solve \: for \: x: \n = > r = \sqrt{ (ax - p)/(q + bx) } \n \n </p><p>r = \sqrt{ (ax - p)/(q + bx) } \: is \: equivalent \: to \: \sqrt{ (ax - p)/(q + bx) } = r :\n = > \sqrt{ (ax - p)/(q + bx) } = r \n \n Raise \: both \: sides \: to \: the \: power \: of \: two: \n = > (ax - p)/(q + bx) = {r}^(2) \n \n Multiply \: both \: sides \: by \: (q + b x): \n = > ax - p = {r}^(2) (q + bx) \n \n Expand \: out \: terms \: of \: the \: right \: hand \: side: \n = > ax - p = q {r}^(2) + b {r}^(2)x \n \n Subtract \: b {r}^(2)x - p \: from \: both \: sides: \n = > x(a - b {r}^(2) ) = p + q {r}^(2) \n \n Divide \: both \: sides \: by \: a - b {r}^(2) : \n = > x = \frac{p + q {r}^(2) }{a - b {r}^(2) }$

Use mathematical induction to prove the statement is true for all positive integers n. The integer n3 + 2n is divisible by 3 for every positive integer n.

Answers

1. prove it is true for n=1
2. assume n=k
3. prove that n=k+1 is true as well

so

1.
$(n^3+2n)/(3)$ =
$(1^3+2(1))/(3)$ =
$(1+2)/(3)$ =1
we got a whole number, true

2.
$(k^3+2k)/(3)$
if everything clears, then it is divisble

3.
$((k+1)^3+2(k+1))/(3)$ =
$((k+1)^3+2(k+1))/(3)$ =
$(k^3+3k^2+3k+1+2k+2))/(3)$ =
$(k^3+3k^2+5k+3))/(3)$
we know that if z is divisble by 3, then z+3 is divisble b 3
also, 3k/3=a whole number when k= a whole number

$(k^3+2k)/(3) + (3k^2+3k+3)/(3)$ =
$(k^3+2k)/(3) + k^2+k+1$ =
since the k²+k+1 part cleared, it is divisble by 3

we found that it simplified back to $(k^3+2k)/(3)$

done

Answer:

We have to use the mathematical induction to prove the statement is true for all positive integers n.

The integer $n^3+2n$ is divisible by 3 for every positive integer n.