A survey of 80 students found that 24 students both play in the band and play a sport. But 22 students are not in band and do not play a sport. There are 48 students in the band. If being in band is the row variable and playing sports is the column variable, fill in the labels in the table. A 4-column table with 3 rows. Column 1 has entries in band, not in band, total. Column 2 is labeled play a sport with entries a, d, g. Column 3 is labeled do not play a sport with entries b, e, h. Column 4 is labeled total with entries c, f, i.

Which of the following correctly represents the given data in the problem?

A: a = 24, g = 48, h = 22, i = 80
B: a = 22, c = 80, d = 24, i = 48
C: a = 24, b = 48, c = 22, i = 48
D: a = 24, c = 48, e = 22, i = 80

Answers

Answer 1
Answer:

Answer:

It's D

Step-by-step explanation:

I took the lesson E2020

Answer 2
Answer:

Answer:

b = 24

d = 10

f = 32

g = 34

h = 46

Step-by-step explanation:


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Evaluate b2c-1 for b = 8 and c = -4. -16 1/16 16 256

Answers

Answer:  The correct option is (B) -16.

Step-by-step explanation:  We are given to evaluate the value of the following expression for b = 8 and c = -4 :

E=b^2c^(-1).

To find the value of expression (i), we need to substitute the values of b and c in equation (i).

We will be using the following property of exponents :

x^(-a)=(1)/(x^a).

Therefore, from equation (i), we get

E\n\n=b^2c^(-1)\n\n=8^2* (-4)^(-1)\n\n\n=(64)/(-4)\n\n=-16.

Thus, option (B) is correct.

b²c-¹ = (8)²(–4)-¹ = 64(–¼) = –16

Find the sample space for tossing 2 coins. Then find P(exactly 1 head).A. 1/8
B. 1/2
C. 3/4
D. 1/4

Answers

HH,HT,TT,TH
As evident from above sample space,the probability of finding exactly one Head 2\4 I.E 1\2
so the answer is B

Option B. (1)/(2) is correct.

What is probability?

Possible chances of occurring an event are known as the probability of that event.

Sample space for tossing two coins is :

( {H,H} , {H,T} , {T,T} , {T,H} )

Formula used:

Probability of an event = (favourable)/(Total)

Exactly one head appeared 2 times i.e., {H,T} or {T,H}

Thus, Favourable outcomes = 2

Total outcomes = 4

P (Exactly one head) = (2)/(4) = (1)/(2)

To know more about Probabilities visit:

brainly.com/question/24756209

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Determine whether AB and C D are parallel, perpendicular, or neither.A (8,4), B (4, 3), C (4, -9), and D (2, -1)

Answers

Answer:

To determine whether AB and CD are parallel, perpendicular, or neither, we need to analyze their slopes.

The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the slope formula:

slope = (y2 - y1) / (x2 - x1)

Let's calculate the slopes of AB and CD:

AB:

Point A (8, 4)

Point B (4, 3)

slope of AB = (3 - 4) / (4 - 8) = -1 / -4 = 1/4

CD:

Point C (4, -9)

Point D (2, -1)

slope of CD = (-1 - (-9)) / (2 - 4) = 8 / -2 = -4

Now, let's analyze the slopes:

1. If the slopes of AB and CD are equal, then the lines are parallel.

In this case, the slope of AB is 1/4 and the slope of CD is -4. Since the slopes are different, AB and CD are not parallel.

2. If the product of the slopes is -1, then the lines are perpendicular.

In this case, the product of the slopes of AB and CD is (1/4) * (-4) = -1. Since the product is -1, AB and CD are perpendicular.

Therefore, AB and CD are perpendicular to each other.

In summary, AB and CD are perpendicular lines.

Step-by-step explanation:

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Help me please1. In ABC, centroid D is on median . AD = x + 5 and DM = 2x – 1. Find AM.
Picture on bottom

Answers

(3x+4) units.

Working;
AM=AD+DM
      =x+5+2x-1
      =(3x+4) units

Which represents a quadratic function?f(x) = −8x3 − 16x2 − 4x

f (x) = x 2 + 2x − 5

f(x) = + 1

f(x) = 0x2 − 9x + 7

Answers

A quadratic function is one of the form f(x) = ax^2 + bx + c, where a, b, and c are numbers with a not equal to zero. In the given question, the only function that satisfies the condition of a quadratic function is f(x) = x^2 + 2x - 5 and thus is the correct answer to the question.

Answer:

f (x) = 3/4 x ^2 + 2x − 5

Step-by-step explanation:


At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold.The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

Answers

Answer:

Here, x represents the umber of food tickets sold and  y represents the number of ride tickets sold.

Given the system of equations:

2x+3y = 1240         ....[1]

x = 2y-10              ....[2]

Substitute the equation [2] into [1] we have;

2(2y-10)+3y = 1240

Using distributive property,

a \cdot(b+c) = a\cdot b+ a\cdot c

4y-20+3y = 1240

Combine like terms;

7y-20 = 1240

Add 20 to both sides we have;

7y= 1260

Divide both sides by 7 we have;

y = 180

Substitute this in [2] we have;

x = 2(180)-10 = 360-10 = 350

therefore, each type of ticket were sold are:

the number of food tickets sold is, 350 and the number of ride tickets sold is, 180

2(2y-10)+3y=1240
7y-20=1240
7y=1260
y=180
2x+3(180)=1240
2x+540=1240
2x=700
x=350
So they sold 350 food tickets and 180 ride tickets in total.
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