The atomic number of an element is equal to the number of _____ contained in one atom of that element.

Answers

Answer 1
Answer: the atomic number of an element is equal to the number  of protons in an atom  

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Which of the following is NOT a stage of cellular respiration?a. fermentation
b. electron transport
c. glycolysis
d. Krebs cycle

Answers

Fermentation is the stage where it is not part of the cellular respiration. The answer is letter A. fermentation does not require oxygen to do respiration, rather, these are the glycolysis, Kreb’s cycle and electron transport.

Fermentation is NOT a stage of cellular respiration. Therefore option A is correct.

Fermentation is not a stage of cellular respiration. Cellular respiration is the process by which cells break down glucose and other organic molecules to produce energy in the form of ATP (adenosine triphosphate).

It occurs in three main stages: glycolysis, the Krebs cycle (also known as the citric acid cycle or the tricarboxylic acid cycle), and the electron transport chain.

Fermentation is an alternative metabolic pathway that occurs in the absence of oxygen (anaerobic conditions). It is a partial breakdown of glucose or other organic molecules that do not involve the complete oxidation of glucose to produce ATP.

Instead, it produces a small amount of ATP and end products such as lactic acid or ethanol.

Therefore option A is correct.

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Sunlight is a form of electromagnetic energy.
a. True
b. False

Answers

It is true that sunlight is a form of electromagnetic energy. Electromagnetic energy is a form of radiant energy that released by electromagnetic radiation. One example of an electromagnetic radiation is the visible light. And visible light can be radio waves, infrared light and X - rays. The rays of the sun are a form of visible light. It has an electromagnetic radiation of UV (ultra violet) rays. That is why the radiation at day is greater than at day due to sun’s rays. 

A photon with a frequency of 5.48 × 10^14 hertz is emitted when an electron in amercury atom falls to a lower energy level.

Calculate the energy of this photon in joules. [Show all work, including the equation and substitution with
units.]

Answers

The energy of the photon in joules, given that it's has a frequency of 5.48×10¹⁴ Hz is36.33×10¯² J

Data obtained from the question

  • Frequency (f) = 5.48×10¹⁴ Hz
  • Energy (E) =?

How to determine the energy

  • Planck's constant (h) = 6.63×10¯³⁴ Js
  • Frequency (f) = 5.48×10¹⁴ Hz
  • Energy (E) =?

The energy of the photon can be obtained as follow:

E = hf

E = 6.63×10¯³⁴ × 5.48×10¹⁴

E = 36.33×10¯²⁰ J

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     Using the Planck's Equation, comes:

E=hf \n E=6.63*10^(-34)*5.48*10^(14)*J \n \boxed {E=36.3324*10^(-20)*J}

If you notice any mistake in my english, please let me know, because i am not native.

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?

Answers

a=acceleration
vf=final velocity
v₀=original velocity
t=time period

a=(vf-v₀)/t
a=(98 m/s-65 m/s)/12s=33 m/s / 12 s=2.75 m/s²

Answer: the acceleration of the object is 2.75 m/s²

     Size of acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

                             =     (98 m/s)    -    (65 m/s)  =  33 m/s .

Time for the change = 12 s

Size of acceleration =  (33 m/s) / (12 s)

                                   =    (33/12) (m/s²)

                                   =        2.75 m/s² .

The position of an object moving along a line at any time t 2 0 is given by the function s(t) = t3 – 9t2 + 18, where s is measured in feet and t is measured in seconds. A) Find the velocity of the particle at t = 4.

Answers

Answer:

S = t^3 - 9 t^2 + 18          position of particle

V = dS / dt = 3 t^2 - 18 t     speed of particle at time t

V = 3 * 4^2 - 18 * 4 = 48 - 72 = - 24 ft/sec

 

What would be the meaning of a nonzero y intercept to a graph of total mass versus volume?

Answers

It would imply the object has some volume but 0 mass which isn't possible. Negligible masses with volumes can be considered however absolutely 0 mass really means the object doesn't exist at all. Thus, showing the graph is wrong.