The balanced chemical reaction is:
2Al2O3 = 4Al +3 O2
We are given the amount of the reactant. This will be the starting point of our calculations.
26.5 mol Al2O3 ( 3 mol O2 / 2 mol Al2O3 ) = 39.75 mol O2 needed
Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
the balanced chemical equation for the decomposition of Al₂O₃ is as follows
2Al₂O₃ --> 4Al + 3O₂
stoichiometry of Al₂O₃ to O₂ is 2:3
when 2 mol of Al₂O₃ decomposes - 3 mol of O₂ are formed
therefore when 26.5 mol of Al₂O₃ decomposes - 3/2 x 26.5 mol = 39.75 mol
the number of moles of O₂ formed are 39.75 mol
Answer:
There are chemical cross-links between the two strands in DNA, formed by pairs of bases. They always pair up in a particular way, called complementary base pairing: thymine pairs with adenine (T–A) guanine pairs with cytosine (G–C)
Explanation:
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Given:
10g of potassium chlorate decomposed
STP
molar mass of KClO3 is 122.55 g/mol
Required:
Volume of oxygen gas
Solution:
The decomposition reaction is
2KClO3 → 2KCl + 3O2
Moles of O2 = 10g KClO3 (1 mol KClO3/122.55 g/mol KClO3)(3 moles O2/2 moles KClO3) = 15 moles O2
Using ideal gas law: PV = nRT
PV = nRT
V = nRT/P
V = (15 moles O2)(0.08206 L-atm/mol-K)(273K)/1 atm
V = 336.04 L O2
B....Energy is removed from the particles in each change, but more energy is removed in boiling than in melting because the attractions are weaker.
C....Energy is added to the particles in each change, but boiling requires more energy than melting because the attractions must be completely overcome.
D....Energy is added to the particles in each change, but melting requires more energy than boiling because the attractions must be completely overcome.
C. Energy is added to the particles in each change, but boiling requires more energy than melting because the attractions must be completely overcome.
Answer:
Humidity
Explanation:
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4% of the mass of air. Hot air can hold more water vapor than cold air, so the amount of water vapor is highest in hot, tropical areas and lowest in cold, polar regions
Explanation: