x+^4+x^3+4x^2+10x-9...............................
Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
answer:
3b²
step-by-step explanation:
(5a² - b²) - (4a² + 3b²) - (a² - 7b²)
= 5a² - b² - 4a² - 3b² - a² + 7b²
= 3b²
the standard equation for a circle is: (x-a)^2 + (y-b)^2 = m^2
x-a)^2 + (y-b)^2 = m^2
means(x-a)(x-a) + (y-b)(y-b) = m^2 then you foil
x^2 - 2ax + a^2 + y^2 - 2by + b^2 = m^2