(2) hydrogen carbonate (4) oxalate
Answer: The correct option is 2.
Explanation: Polyatomic ions are defined as the ions in which two or more elements are covalently bonded to act as a single unit. They always carry some charge.
Examples of polyatomic ions are: known as hydroxide ion, known as sulfate ion
We are given a compound having 2 ions which are and . these ions are named as sodium ions and hydrogen carbonate ions.
Therefore, the correct option is 2.
Η Ο Η
TIL 1
H-C-C-C-H
1-CI
lodine monochloride, ICI
H
H
Acetone, C3H60
H-F
A mixture of water (H2O) and hydrogen fluoride
(HF)
Answer:
London dispersion, dipole-dipole interactions, hydrogen bonding
Explanation:
Please mark brainliest
Answer:
lodine monochloride- dipole-dipole interactions
Acetone-London dispersion
A mixture of water (H2O) and hydrogen fluoride-hydrogen bonding
Explanation:
Edg 2020 (Brainliest Lol)
b. nickel.
c. brass.
d. cadmium.
Answer:
Taskmasters is Correct. The answer is Choice B.
I just took the quiz and got it Correct.
Explanation:
It is known that the atomic number of sodium is 11 and its electronic distribution is 2, 8, 1.
As the number of rows (called periods) in the periodic table represent the number of shells present in an element.
Since, sodium element have only two shells. Therefore, sodium lies in row 2 of the periodic table.
Also, the elements which contain same number of valence electrons lie in the same group.
Therefore, sodium belongs to group 1 and elements of the group 1 are also known as alkali metals.
Thus, we can conclude that in the periodic table sodium lies in period 2 and group 1.
(B) 0.010 M
(C) 0.10 M
(D) 1.0 M
The molarity of the NaOCl solution is 0.10M
The correct answer to the question is Option C. 0.10 M
We'll begin by calculating the number of mole of NaOCl required to produce 0.010 mole of Cl₂.This can be obtained as follow:
NaOCl + 2HCl —> Cl₂ + NaCl + H₂O
From the balanced equation above,
1 mole of NaOCl reacted to produce 1 mole of Cl₂.
Therefore
0.010 mole of NaOCl will also react to produce 0.010 mole of Cl₂.
Mole of NaOCl = 0.01 mole
Volume = 100 mL = 100 / 1000 = 0.1 L
Molarity = mole / Volume
Molarity of NaOCl = 0.01 / 0.1
Therefore, the molarity of the NaOCl solution is 0.1 M
Learn more: brainly.com/question/12755239
Answer:
Option C 0.10 M
Explanation:
you are not providing the reaction, but luckily we have data to write the equation. We know that we are taking HCl and NaOCl to produce Cl2, the reaction is as follow:
NaOCl + 2HCl ---------> Cl₂ + NaCl + H₂O
From this reaction, we know that we have excess of acid that is added to 100 mL (0.1 L) of NaOCl, and this produces 0.010 moles of Chlorine.
All we have to do here, is apply stechiometry. We already know that the acid is in excess, so the moles produced would be the moles of the limiting reactant, in this case, the NaOCl.
According to the reaction NaOCl and Cl2 has a mole ratio of 1:1, so the moles of Cl2 would be the same moles that NaOCl lost so:
moles Cl2 = moles NaOCl = 0.010 moles
Then the concentration:
M = 0.010 / 0.1
M = 0.10 M
This is the molarity of NaOCl