B-eccentricity of orbit
C- period of rotation
D-period of revolution
Copper (II)iodide
Tin(IV) nitride
Choro minim (II)bromide
Iron(III)phosphide
Compounds are classified as binary or ternary based on the number of elements present in the compound. The chemical formulas for the given compounds include nickel(III)oxide, copper(II)iodide, tin(IV)nitride, chloro minimium(II)bromide, and iron(III)phosphide.
In order to identify whether a compound is binary or ternary, we need to analyze its chemical formula. Binary compounds consist of two elements, while ternary compounds consist of three or more elements. The chemical formula for each compound is as follows:
#SPJ2
Answer:
Considering the reaction stoichiometry and the definition of limiting reagent, the mass of AlCl₃ that is produced when 10.0 grams of Al₂O₃ react with 10.0 grams of HCl is 12.19 grams.
Explanation:
Al₂O₃ + 6 HCl → 2 AlCl₃ + 3 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Al₂O₃: 1 mole
HCl: 6 moles
AlCl₃: 2 moles
H₂O: 3 moles
The molar mass of the compounds present in the reaction is:
Al₂O₃: 102 g/mole
HCl: 36.45 g/mole
AlCl₃: 133.35 g/mole
H₂O: 18 g/mole
Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:
Al₂O₃: 1 mole× 102 g/mole= 102 grams
HCl: 6 moles× 36.45 g/mole= 218.7 grams
AlCl₃: 2 moles× 133.35 g/mole= 266.7 grams
H₂O: 3 moles× 18 g/mole= 54 grams
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 102 grams of Al₂O₃ reacts with 218.7 grams of HCl, 10 grams of Al₂O₃ reacts with how much moles of HCl?
mass of HCl= 21.44 grams
But 21.44 grams of HCl are not available, 10 grams are available. Since you have less moles than you need to react with 10 grams of Al₂O₃ , HCl will be the limiting reagent.
Then, it is possible to determine the mass of AlCl₃ produced by another rule of three: if by stoichiometry 218.7 grams of HCl produce 266.7 grams of AlCl₃, if 10 grams of HCl react how much mass of AlCl₃ will be formed?
mass of AlCl₃= 12.19 grams
In summary, the mass of AlCl₃ that is produced when 10.0 grams of Al₂O₃ react with 10.0 grams of HCl is 12.19 grams.
Answer:
O-16 isotope is most likely to have the greatest abundance in nature.
Explanation:
Atomic mass of an isotopes of oxygen elements:
Average atomic mass of an oxygen atom = 15.994 amu
Isotope with the value of atomic mass closest to the average atomic mass of the oxygen atom will have the greatest abundance in nature. As it will be found in much more greater extent in nature.
Where as isotope which is least close to the average atomic mass will have less abundance in nature.
O-16 isotope is most likely to have the greatest abundance in nature.
15.995 amu ≈ 15.994 amu