MATHEMATICS HIGH SCHOOL

In how many ways can 12 basketball players be listed in a program?A. 12

B. 479,001,600

C. 665,280

D. 1

Answers

Answer 1
Answer:

Answer:  B. 479,001,600

Step-by-step explanation:

We know that the number of possible combination objects from a set where order matters is given by using permutations.

Given: The number of basketball players = 12

By using permutations, the number of ways the basketball players can be listed is given by :-

12!=12*11*10*9*8*7*6*5*4*3*2*1\n\n=479,001,600
Answer 2
Answer:

Answer:

B. 479001600

Step-by-step explanation:

We are asked to find the number of ways can 12 basketball players be listed in a program.

We will use permutations to solve our given problem.

There are 12 ways to choose 1st player for the team.

Since 1 player is already chosen, so we can choose 2nd player in 11 ways. Similarly we can choose 3rd player in 10 ways.

\text{The number of ways 12 basketball players to be listed in a program}=12!

12!=12*11*10*9*8*7*6*5*4*3*2*1

\text{The number of ways 12 basketball players to be listed in a program}=479001600

Therefore, in 479001600 ways can be 12 basketball players be listed in a program and option B is the correct choice.

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Answers

nearest tenths would be = .8
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A cone has a volume of 6 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?

Answers

36 in. to the 3rd...........

A rectangle has a perimeter of 26 cm and one of its sides has a length of 5 cm sketch a rectangle and label all of its sides lengths

Answers

Answer:

Step-by-step explanation:

Perimeter of rectangle given = 26 cm

And measure of a side of the rectangle = 5 cm

Since perimeter of a rectangle = 2(length + width)

By replacing the values of perimeter and length in the formula

26 = 2(5 + width)

5 + width = (26)/(2)=13

width = 13 - 5 = 8 cm

Now we can draw a rectangle of length = 5 cm and width = 8 cm  
im thinking both shorter sides are 5cm, and the 2 longer sides are 8cm each... add them all together and you get 26cm

PLEASE HELPHow many different outcomes are possible when 10 people race, assuming no one can tie?

Answers

The number of the outcomes will be 10 if there is not any tie.

What is the combination?

The arrangement of the different things or numbers in a number of ways is called the combination.

Here we need to find the outcomes of the winning of 10 people the combination will be:-

^(10) C _1=(10!)/((10-1)!)=(10!)/(9!)\n\n\n^(10) C _1 = 10

Hence the number of the outcomes will be 10 if there is not any tie.

To know more about combinations follow

brainly.com/question/11732255

#SPJ2
There are 10 possible outcomes because 1 can win if there are no ties.

Find the product of 543 and 36.
A. 507
B. 19,548
C. 15.08
D. 579

Answers

1 Set up the long multiplication.

543x36

2 Calculate 3 x 6, which is 18.
Since 18 is two-digit, we carry the first digit 1 to the next column.

3 Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.

4 Calculate 5 x 6, which is 30. Now add the carry digit of 2, which is 32.
Since 32 is two-digit, we carry the first digit 3 to the next column.

5 Bring down the carry digit of 3.

6 Calculate 3 x 3, which is 9.

7 Calculate 4 x 3, which is 12.
Since 12 is two-digit, we carry the first digit 1 to the next column.

8 Calculate 5 x 3, which is 15. Now add the carry digit of 1, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.

9 Bring down the carry digit of 1.

10 Calculate 3258 + 16290, which is 19548


11 Therefore, 543 x 36 = 19548.

The answer is B.19548
B. 19,548 because a product is an aswer in amultipacation problem so you would have to multiply 543 x 36

PLZ HELP ASAP2. One load of gravel contains 240 ft2 of gravel. The area A that the gravel will cover is inversely proportional to the depth of d to which the gravel is spread.
a. Write an inverse variation model for the relationship between the area and depth for one load of gravel.
b. A designer plans a playground with gravel 6 in. deep over the entire play area. If the play area is a rectangle 40 ft. wide and 24 ft long, how many loads of gravel will be needed? (4 points)

I understand everything else but this question.

Answers

Answer:

A. y= (z*240ft\n\n^(3) )/(x)

B. z= 2

Step-by-step explanation:

A.

The format for the inverse variation formula is y =  

This is a bit different compared to the format of directly variation formula y= kx

In this case, one load of gravel have 240 ft^(3)volume. The area is inversely proportional with depth, so formula for the volume is Area x Depth (V= A x D). The inverse variation formula will be: A= V/D

If the number of loads=z, each load is 240 ft^(3), area = y and depth = x , then the model will be:

y= (z*\nk)/(x)

y= (z*240ft\n\n^(3) )/(x)

B.

The play area is  a rectangle 40 ft wide and 24 ft long, then the area will be: area = 40ft * 24ft= 960 ft^(2)

We have area(y= 960 ft^(2)) and depth(x= 6 in- 0.5 ft) , now we can find out the number of loads needed(z) by using the equation.

y= (240ft*z\n\n^(3) )/(x)

960 ft^(2)= (z*240ft\n\n^(3) )/(x)

480 ft^(2) * z= 960 ft^(2)

z= (960ft^(2) )/(480ft^(2))= 2
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