what is the equation of the line that passes through the points (-1,3) and (0,1)?
Answer:
y = -2x + 1
Step-by-step explanation:
Slope m = (y2-y1)/(x2-x1)
using (-1,3) and (0,1)
m = (1 - 3)/(0 - -1)
m = (-2)/(1) = -2
Slope-intercept: y = mx + b
using (-1,3)
then 3 = -2(-1) + b
3 = 2 + b
b = 1
y = -2x + 1