PHYSICS HIGH SCHOOL

What did the protoplanets become?a. nebulae
b. planets
c. solar nebulae
d. planetesimals

Answers

Answer 1
Answer:

What did the protoplanets become?

a. nebulae
b. planets
c. solar nebulae
d. planetesimals

The protoplanets become nebulae. The answer is letter A. The rest of the choices do not answer the question above.
Answer 2
Answer:

The answer is B. Planets

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How does wavelength relate to frequency?

Answers

The larger the wavelength the lower the frequency, and the smaller the wavelength the higher the frequency 

A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m ​ 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13 \,\dfrac{\text m}{\text s}13 s m ​ 13, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with a constant acceleration of 2.0 \,\dfrac{\text m}{\text s^2}2.0 s 2 m ​ 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction rightward.

Answers

Answer: 38.25 m

Explanation:

In this situation we need to find the distance d between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant:

V^(2)=V_(o)^(2) + 2ad(1)

Where:

V=13 m/s is the rabbit's maximum velocity (final velocity)

V_(o)=4 m/s is the rabbit's initial velocity

a=2 m/s^(2) is the rabbit's acceleration

d is the distance between the rabbit and the carrot

Isolating d:

d=(V^(2)-V_(o)^(2))/(2a)(2)

d=((13 m/s)^(2)-(4 m/s)^(2))/(2(2 m/s^(2)))(3)

Finally:

d=38.25 m

Answer:

4.5s

Explanation:

Cause that's what it says on my test hints

If you were on the open ocean on a large ship, how could you determine the height of a wave?

Answers

If I were on the open ocean on a large ship, the way on how I can determine the height of a wave would be simply looking at the marks it leaves on the sides of the ship as it hits it. The wet part can be an estimate on the height of the wave.

How does matter and energy move through the water cycle

Answers

energy moves through an ecosystem when an organism is eaten. As you go up each trophic level, 10% of energy is transferred up. Matter on the other hand, is neither lost or gained. so it just moves up the trophic levels
I have attached a photo to explain. (:

A soda bottle is flexible enough that the volume of the bottle can change even without opening it. If you have an empty soda bottle (volume of 2.0 L) at room temperature (25 0C), what will the new volume be if you put it in your freezer (-4.0 0C)?

Answers

Answer: 1.81 L

Explanation:

Let us assume that we are dealing with an ideal or perfect gas. Thus we can use the formula from Charles' law that relates the volume with respect to the temperature of a gas.

Given:

Initial volume (V1) = 2L

Initial temperature (T1) = 25°C = 273 + 25 = 298 K

Final temperature (T2) = -4°C = 273 - 4 = 269 K

Final Volume (V2) = ?

Using Charles' law like we stated above, we have

(V1) / (T1) = (V2) / (T2), making V2 the subject of formula, we have

V2 = (V1 × T2) / T1

V2 = (2L × 269 K) / (298 K)

V2 = 538 L.K / 298 K

V2 = 1.81 L

Indicar tipo de unión química que presentan los siguientes compuestos. Realizar a representación de Lewis, molecular o iónica, según corresponda: a-CH4 b-SrO c-HBr d-NH3 e-Cl2O f-Li2O g-CO2 h-MgCl2

Answers

Answer:

Explanation:

a. CH₄- Covalent bonding(ligação covalente)

b. SrO- ionic bonding (ligação iônica)

c. HBr- Polar Covalent bonding (ligação covalente polar)

d. NH₃ - covalent bonding(ligação covalente)

e. Cl₂O - Covalent bonding (ligação covalente)

f. Li₂O- ionic bonding (ligação iônica)

g. CO₂ - double covalent bonding (ligação covalente dupla)

h. MgCl₂- ionic bonding(ligação iônica)
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