Answer:
D. 1.7
Explanation:
Refractive index can be calculated using the formula;
η =real depth/apparent depth
Assume the real depth to be-----x
Apparent depth will be : 40% less than real depth;
60/100 *x =0.6x
η = x/ 0.6 x
η = 1/0.6
η= 10/6
η = 1.66
η = 1.7
Answer:
The minimum current rating of the motor disconnecting means is 165 Amperes.
Explanation:
First convert the given power into units of watt. Since,
1 horsepower = 746 watts
Therefore,
40 horsepower = 40 x 746 watts
40 horsepower = 29840 watts
Since, we know that:
Power = Full Load Current (FLC) x Voltage
FLC = Power/Voltage
FLC = 29840 watts/208 volts
FLC = 143.46 Amperes
Now, the current for disconnecting means is at least 115% of the FLC, for the motors rated at 600 Volts or less.
Current for Disconnecting Means = (1.15)(143.46 A)
Current for Disconnecting Means = 165 Amperes
The displacement vector, d, can be recomposed as follows: d = (Dx, Dy) and the magnitude of the displacement vector is approximately 11.24 meters.
To recompose the displacement vector, d, using the given X and Y components, you can use vector addition. The X and Y components represent the horizontal and vertical displacements, respectively.
Given:
Dx = 6.68 m (left)
Dy = 9.04 m (down)
The displacement vector, d, can be recomposed as follows:
d = (Dx, Dy)
So, the displacement vector is (6.68 m left, 9.04 m down). This means that the object moved 6.68 meters to the left (in the negative X direction) and 9.04 meters downward (in the negative Y direction) from its starting point.
The magnitude of the displacement can be found using the Pythagorean theorem:
|d| = √((Dx)^2 + (Dy)^2)
|d| = √((6.68 m)^2 + (9.04 m)^2)
|d| ≈ √(44.49 m^2 + 81.72 m^2)
|d| ≈ √(126.21 m^2)
|d| ≈ 11.24 meters
So, the magnitude of the displacement vector is approximately 11.24 meters.
Learn more about displacement vector here:
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a. N
b. N-s
c. N-s2
d. N/s