Answer:
D. decomposition
Explanation:
Synthesis reaction occurs when two elements or compounds react to originate a new one:
A + B ⇒ C
Combustion occurs when a fuel reacts with oxygen to form CO₂ and water:
A + O₂ ⇒ CO₂ + H₂O
Replacement reaction can be simple or double. Simple occurs when a simple element replaces others in a compound:
A + BC ⇒ B + AC
Double occurs when two compounds replace elements between them:
AB + CD ⇒ AC + BD
Decomposition reaction occurs when a compound originates two or more compounds
A ⇒ B + C
So, the reaction given is a decomposition chemical reaction.
2MgO → 2Mg + O2 is an example of a decomposition chemical reaction. The answer is letter D. It is not a replacement reaction because no other compound is involved. It is not a combustion reaction because no oxygen is involved.
(2) 29.2%
(3) 58.4%
(4) 87.5%
The percentage composition by mass of nitrogen in is .
Further explanation:
The most commonly applied concentration terms are as follows:
1. Molality
2. Mole fraction
3. Molarity
4. Parts per million
5. Mass percent
6. Volume percent
7. Percentage composition
The given compound is . It contains two atoms of nitrogen, eight atoms of hydrogen, one atom of carbon and three atoms of oxygen.
The mass of nitrogen in can be calculated as follows:
…… (1)
The number of N atoms in is 2.
The molar mass of nitrogen is 14.01 g/mol.
Substitute these values in equation (1).
The formula to calculate the percentage composition of N in is as follows:
…… (2)
The mass of N is 28.02 g/mol.
The mass of is 96.0 g/mol.
Substitute these values in equation (2).
Therefore the percentage composition by mass of nitrogen in is 29.2 %.
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Answer details:
Grade: Senior School
Chapter: Concentration terms
Subject: Chemistry
Keywords: (NH4)2CO3, N, nitrogen, mass, 2.92 %, 96.0 g/mol, 28.02 g/mol, nitrogen, hydrogen, carbon, oxygen, mass of N, mass of (NH4)2CO3.
The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.
The percent composition of nitrogen in ammonium carbonate can be calculated as:
% Composition =
Mass of nitrogen in the compound has been:
Number of Nitrogen atoms = 2
Mass of 1 nitrogen atom = 14 g/mol
Mass of 2 nitrogen atom = 28 g/mol
Mass of compound = 96 g/mol
% Composition of nitrogen =
% Composition of nitrogen = 29.166 %
The % composition of nitrogen is 29.166% ~ 29.2%. Thus option 2 is correct.
For more information about the percent composition, refer to the link:
The lattice structure of Lithium Fluoride (LiF) is comprised of positively charged lithium ions (Li+) and negatively charged fluoride ions (F-) that a linked together by ionic bonds.
The crystal structure of LiF corresponds to that of a face centered cubic (FCC) lattice with Li+ and F- ions occupying the lattice points in the unit cell.
Answer:
Explanation:
An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.
Lithium fluoride is a chemical compound formed through a chemical bond of formula LiF. The electronic configuration of Li is 1s12s1 and that of fluorine is 1s12s22p5. When these atoms come into contact, the 2s1 valence electron of the lithium is transferred to the F atom.
Ionic solids can crystallize in various types of networks, depending on the size of the ions that form it and the charge they possess.
The solid NaCl has a crystalline structure, in which each Na + ion is surrounded by six chloride ions in an octahedral geometry. Therefore, it has a coordination (6: 6) whose numbers indicate how many neighbors surround each ion. The number on the right indicates the neighbors of Na +, while the one on the left, those of Cl–. The structure is based on a compact cubic packing (centered on the faces) of the anions and in which the cations occupy all the octahedral holes. The structure can also be seen as a compact cation packing structure with the anions occupying the octahedral holes. In each unit cell ions of one type occupy the vertices and centers of the faces of the cube while those of the opposite sign are located in the centers of the edges and in the center of the cube.
The density of Argon gas at a pressure of 753 mmHg and a temperature of 35 °C is equal to 1.59 g/L.
The state of a quantity of gas is calculated by its pressure, volume, and temperature. The ideal gas law can be explained as the product of the volume and pressure of gas is equal to the multiplication of the universal gas constant and absolute temperature.
The mathematical equation for an ideal gas can be written as follows:
PV = nRT
PV =(m/M) RT
PM/RT = m/V
d = PM/RT
Where n is the moles of gas, T is the temperature of the gas, V is the volume of the gas, and R is the gas constant.
Given, the temperature of argon gas, T = 35 °C = 35 +273 = 308 K
The pressure of the argon gas, P = 753 mmHg = 1.01 atm
The molar mass of the Argon gas, M = 40 g/mol
Substitute V, R, P, and T in the ideal gas equation, we get:
The density of Argon gas, d = PM/RT
d= 1.01 ×40/(0.082 × 308)
d = 1.59 g/L
Therefore, the density of Ar gas is 1.59 g/L.
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