When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor?

Answers

Answer 1
Answer: This can be answered by manipulating the formula for the coefficient of kinetic friction, which is as follows:

Let: μ = coefficient of kinetic friction
F = force
N = normal force

μ = F / N

Substituting the given values:

0.23 = 27N / N
N = 27 / 0.23
N = 117.39 N

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Nuclear power plants produce _______.a. radioactive waste that must be stored properly
b. no waste
c. radioactive waste that can be released into local water supplies
d. air pollution

Answers

Nuclear power plants produce radioactivewaste that must be stored properly. It is very impossible for a nuclear power plantto have no waste at all since lots of chemicals are used to create the processas it gives energy to other machines. Radioactive waste can not be releasedinto local water supplies since the wastes are very radioactive and may causemutation to the fishes and bioaccumulation which will affect humans as well. Itwill also cause air pollution if the chemicals are not stored properly.

Nuclear power plants produce radioactive waste that must be stored properly in other to prevent pollution and health hazards.

What is nuclear power plants?

Nuclear power plant refer to the thermal power station in which power is generated and the the heat source is a nuclear reactor. In any thermal power stations, heat is used to generate steam that spin up steam turbine connected to a generator that produces electricity.

Therefore, Nuclear powerplants produce radioactive waste that must be stored properly.

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Most earthquakes are produced by the rapid release of which kind of energy stored in rock subjected to great forces?a. kinetic
b. thermal
c. elastic
d. mechanica

Answers

The correct answer for the question that is being presented above is this one: "c. elastic." Most earthquakes are produced by the rapid release of 
elastic energy stored in rocks subjected to great forces. The greater the elasticity of the energy, the more it is subjected to great forces.

Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?

Answers

Answer:

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

Explanation:

According to Coulomb's law, the magnitude of  force between two point object having change q_1 and q_2 and by a dicstanced is

F_c=(1)/(4\pi\spsilon_0)(q_1q_2)/(d^2)-\;\cdots(i)

Where, \epsilon_0 is the permitivity of free space and

(1)/(4\pi\spsilon_0)=9*10^9 in SI unit.

Before  dcollision:

Charges on both the sphere are q_1 and q_2, d=20cm=0.2m, and F_c=1.35*10^(-4) N

So, from equation (i)

1.35*10^(-4)=9*10^9(q_1q_2)/((0.2)^2)

\Rightarrow q_1q_2=6*10^(-16)\;\cdots(ii)

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

(q_1+q_2)/(2)

d=20cm=0.2m, and F_c=1.406*10^(-4) N

So, from equation (i)

1.406*10^(-4)=9*10^9(\left((q_1+q_2)/(2)\right)^2)/((0.2)^2)

\Rightarrow (q_1+q_2)^2=2.50*10^(-15)

\Rightarrow q_1+q_2=\pm5* 10^(-8)

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

\Rightarrow q_1+q_2=5* 10^(-8)\;\cdots(iii)

\Rightarrow q_1=5* 10^(-8)-q_2

The equation (ii) become:

(5* 10^(-8)-q_2)q_2=6*10^(-16)

\Rightarrow -(q_2)^2+5* 10^(-8)q_2-6*10^(-16)=0

\Rightarrow q_2=3*10^(-8), 2*10^(-8)

From equation (iii)

q_1=2*10^(-8), 3*10^(-8)

So, the magnitude of initial charges on both the sphere are 3*10^(-8) Coulombs=0.03 \mu C and 2*10^(-8) Colombs or 0.02 \mu C.

Considerion the nature of charges too,

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

A 60 W light bulb at 120 V is left on in your house to prevent burglary, and the power charges 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days?

Answers

4.22 dollars is the cost to leave the bulb on for 30 days.

What is electrical energy?

Electrical energy is the power an atom's charged particles have to cause an action or move an object. The movement of electrons from one atom to another is what results in electrical energy.

There is a dissipation of electrical energy in the resistor when an electric current flows through it. It depends on the resistance of the resistor and the applied voltage.

The expression of the power dissipation is as follows ;

P=(V^2)/(R)

V is the applied voltage.

R is the resistance.

Given

P  = 60 W

30days * 24h/day = 720 Hours kW * h

Therefore by putting the values in the given formula,

= (60/1000)kW * 720h

= 43.2 kWh

Hence,

The cost is  42.2 kWh42.2 kWh x 0.1

= 4.22 dollars

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Which of the following absorbs the MOST heat energy?a. red objects
b. white objects
c. black objects
d. purple object

Answers

darker is warmer C. Black objects.
Black objects because light waves are attracted to darker objects.

what is the displacement of a cyclist who travels 1 mile north 1 mile east then finally 1 mile south​

Answers

The displacement of a cyclist who travels 1 mile north 1 mile east then finally 1 mile south will be 1 mile in the east direction.

What is the displacement?

A displacement is a vector in engineering and mechanics that has a length equal to the shortest route between a point P's initial and final positions.

The displacement is the vector quantity that depends on the magnitude as well as direction. And follows the law of vector addition.

The cyclist who travels 1 mile north 1 mile east then finally 1 mile south​. Then the diagram is drawn below.

From the graph, the displacement is given as,

Displacement = 1 - 0

Displacement = 1 mile

The displacement of a cyclist who travels 1 mile north 1 mile east then finally 1 mile south will be 1 mile in the east direction.

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The cyclist displacement is 3 miles south