When an object is at a distance of twice the focal length from a concave lens, the image produced is virtual and smaller than the object. What happens to the image if the object is shifted closer to the lens to a point one focal length away from it?The image produced is virtual and enlarged.
The image produced is virtual and smaller than the object.
The image produced is real and enlarged.
The image produced is real and smaller than the object.
The image produced is virtual and of the same size as the object.

Answers

Answer 1
Answer:

Answer:

The image produced is virtual and smaller than the object.

Explanation:

For concave lens we know that

(1)/(d_i) + (1)/(d_o) = (1)/(f)

here we have

(1)/(d_i) + (1)/(2f) = -(1)/(f)

(1)/(d_i) = - (3)/(2f)

d_i = -(2f)/(3)

Magnification will be given as

M = (d_i)/(d_o)

M = -2/3

so image will be virtual and formed behind the lens

Now the object position is shifted to new position at distance of focal length

now again we will have

here we have

(1)/(d_i) + (1)/(f) = -(1)/(f)

(1)/(d_i) = - (2)/(f)

d_i = -(f)/(2)

Magnification will be given as

M = (d_i)/(d_o)

M = -1/2

So again we will have virtual image with magnification 1/2

so here size of image is less than object size by factor of 1/2 and it is virtual

Answer 2
Answer: The right answer for the question that is being asked and shown above is that: "The image produced is virtual and of the same size as the object." the image if the object is shifted closer to the lens to a point one focal length away from it is that The image produced is virtual and of the same size as the object.

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A glass lens, n glass = 1.52 , has a 131 nm thick antireflective film coating one side, n film = 1.25. White light, moving through the air, is perpendicularly incident on the coated side of the lens. What is the largest wavelength of the reflected light that is totally removed by the coating?

Answers

Answer:

655 nm

Explanation:

When the intereference is destructive then the thickness, d of antireflective film coating one side is given by

2d=w/2n

Where w is wavelength and n is the reflective index of the film

Making w the subject of formula then

w=4nd

Substituting 1.25 for n and 131 nm for d then the wavelength will be

w=4*1.25*131=655 nm

Therefore, the wavelength is equivalent to 655 nm

The formula for calculating the wavelength in an antireflective film involves thickness (d) and refractive index (n). For n = 1.25 and d = 131 nm, the resulting wavelength is 655 nm.

When light waves encounter a thin film, some of the waves are reflected from the top surface of the film, and some pass through it. These waves can interfere with each other, leading to constructive or destructive interference. In the case of antireflective coatings, destructive interference is desired to minimize reflection.

The formula you mentioned is used to calculate the thickness (d) of an antireflective film that results in destructive interference for a specific wavelength (w) of light. The formula is:

2d = w / (2n)

Where:

d is the thickness of the film.

w is the wavelength of light.

n is the refractive index of the film.

To find the wavelength (w) when given the thickness (d) and refractive index (n), you can rearrange the formula:

w = 4 * n * d

Now, let's calculate the wavelength using the provided values:

n = 1.25 (refractive index)

d = 131 nm (thickness in nanometers)

Substitute these values into the formula:

w = 4 * 1.25 * 131 = 655 nm

Therefore, the calculated wavelength (w) is 655 nanometers (nm). This means that for a film with a refractive index of 1.25 and a thickness of 131 nm, destructive interference occurs at a wavelength of 655 nm.

For more such information on: wavelength

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Which example best shows how taxonomy can help us understand the evolutionary relationships among species?A-Physical comparisons of species can show how two organisms are related.
B-Phylogenetic trees show evolutionary relationships among organisms.
C-Different species are grouped together.
D-Binomial nomenclature can show the most recent ancestor of two species.

Answers

the example that best shows how taxonomy can help us understand the evolutionary relationships among species is: D-Binomial nomenclature can show the most recent ancestor of two species. by knowing the ancestors of the species we could predict the evolutionary process that happened throguh the genetic combination and mutation
Hi,

The Answer to this question is:


B) Phylogenetic trees show evolutionary relationships among organisms.

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