Answer:
The image produced is virtual and smaller than the object.
Explanation:
For concave lens we know that
here we have
Magnification will be given as
so image will be virtual and formed behind the lens
Now the object position is shifted to new position at distance of focal length
now again we will have
here we have
Magnification will be given as
So again we will have virtual image with magnification 1/2
so here size of image is less than object size by factor of 1/2 and it is virtual
Answer:
655 nm
Explanation:
When the intereference is destructive then the thickness, d of antireflective film coating one side is given by
2d=w/2n
Where w is wavelength and n is the reflective index of the film
Making w the subject of formula then
w=4nd
Substituting 1.25 for n and 131 nm for d then the wavelength will be
w=4*1.25*131=655 nm
Therefore, the wavelength is equivalent to 655 nm
The formula for calculating the wavelength in an antireflective film involves thickness (d) and refractive index (n). For n = 1.25 and d = 131 nm, the resulting wavelength is 655 nm.
When light waves encounter a thin film, some of the waves are reflected from the top surface of the film, and some pass through it. These waves can interfere with each other, leading to constructive or destructive interference. In the case of antireflective coatings, destructive interference is desired to minimize reflection.
The formula you mentioned is used to calculate the thickness (d) of an antireflective film that results in destructive interference for a specific wavelength (w) of light. The formula is:
2d = w / (2n)
Where:
d is the thickness of the film.
w is the wavelength of light.
n is the refractive index of the film.
To find the wavelength (w) when given the thickness (d) and refractive index (n), you can rearrange the formula:
w = 4 * n * d
Now, let's calculate the wavelength using the provided values:
n = 1.25 (refractive index)
d = 131 nm (thickness in nanometers)
Substitute these values into the formula:
w = 4 * 1.25 * 131 = 655 nm
Therefore, the calculated wavelength (w) is 655 nanometers (nm). This means that for a film with a refractive index of 1.25 and a thickness of 131 nm, destructive interference occurs at a wavelength of 655 nm.
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B-Phylogenetic trees show evolutionary relationships among organisms.
C-Different species are grouped together.
D-Binomial nomenclature can show the most recent ancestor of two species.
b. False