Answer:
all atoms of one type were identical in mass and properties
Explanation:
Answer:
1000
Explanation:
kilometer equals to 1000 meters
Answer:
When Iron powder and Sulfur powder are mixed, no chemical reaction will occur, so you will see a physical change. The heterogeneous mixture resulting from mixing Iron powder with Sulfur powder could be easily separated using a magnet. When heating both compounds; however, it is possible to observe a chemical change as Iron Sulfide is formed. This product looks dark, shiny and is solid.
B. [Na +3] / [PO43-]
C. [Na +] }[PO43-)
D. [Na] +3/[PO4) 3 -
The solubility product expression for Na3PO4(s) is [Na+]^3[PO4^3-], which denotes the ion concentration in the solution after the dissolution of sodium phosphate. therefore, option A is correct
The solubility product expression for Na3PO4(s) would be written as [Na+]^3[PO4^3-]. The solubility product, Ksp, is the equilibrium constant for the dissolution of a sparingly soluble substance. The solubility product expression depends on the stoichiometry of the dissolution reaction. Sodium phosphate, Na3PO4, dissociates in water into 3 sodium ions, Na+, and 1 phosphate ion, PO4^3-. Therefore, the solubility product expression is [Na+]^3[PO4^3-], where [Na+] and [PO4^3-] represent the molar concentration of these ions in the solution.
#SPJ6`
The solubility product expression of Na3PO4 is not among the given options because Na3PO4 is soluble in water and for soluble compounds, we don't write a solubility expression.
The solubility product expression is typically written for an ionic compound that is sparingly soluble in water. The solubility product expression of Na3PO4 is not among the options you've provided because every ionic compound has its own specific solubility product expression. Na3PO4 is soluble, so we don't write a solubility expression for it. In general, for a reaction where a solid dissolves in water such as A3B (s) ↔ 3A+ (aq) + B3- (aq), the solubility product expression would be [A+]^3 [B3-].
#SPJ12
Answer:
86.04 %
Explanation:
Data given:
mass of Al = 160.0 g
actual yield Al₂O₃= 260 g
Theoretical yield = ?
percent yield ofAl₂O₃ = ?
Solution:
First we have to find theoretical yield.
So,
we Look at the balanced reaction
4Al + 3O₂ -----—> 2Al₂O₃
4 mol 2 mol
As 4 mole of Al give 2 mole of Al₂O₃
Convert moles to mass
molar mass of Al = 27 g/mol
molar mass of Al₂O₃ = 2(27) + 3(16)
molar mass of Al₂O₃ = 54 + 48
molar mass of Al₂O₃ = 102 g/mol
Now
4Al + 3O₂ -----—> 2Al₂O₃
4 mol (27g/mol) 2 mol (102 g/mol)
108 g 204 g
108 grams of Al produce 204 g of Al₂O₃
So
if 108 grams of Al produce 204 g of Al₂O₃ so how many grams of Al₂O₃will be produced by 160 g of Al.
Apply Unity Formula
108 grams of Al ≅ 204 g of Al₂O₃
160 grams of Al ≅ X of Al₂O₃
Do cross multiply
mass of Al₂O₃= 204 g x 160 g / 108 g
mass of Al₂O₃ = 302.2 g
So the Theoretical yield of Al₂O₃ = 302.2 g
Now Find the percent yield of Al₂O₃
Formula Used
percent yield = actual yield /theoretical yield x 100 %
Put value in the above formula
percent yield = 260g / 302.2 g x 100 %
percent yield = 86.04 %
percent yield of Al₂O₃ = 86.04 %