cancel common factors and then see whats left...
So you cancel (x+5) and 4(5x-3)?
Your CORRECT answer is:
a. quantity x minus 5 over quantity x plus 1, x ≠ −1, x ≠ −9
THIS IS 100% CORRECT!!!
The equation, 9x-6y=-72 in slope-intercept form is .
An equation is a mathematical statement that shows that two mathematical expressions are equal.
The standard form of equation in two variable is y= mx+b,
where y is the dependent variable
x is the independent variable
a is the intercept term
b is the slope
Given the following equation:
9x-6y=-72.......................1
Convert it into standard format y=mx+b,
Divide the equation by 6,
On multiplying the equation by -1.
On solving, to represent it into standard form:
On comparing it with standard equation,
Slope, m=3/2 and Intercept, b=12
Thus, slope-intercept form is .
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A) 200 cubes for a big black boutta
Carson drove a distance of 120120120 kilometers. He initially had 303030 liters of fuel, and his car's fuel efficiency is 100100100 cubic centimeters per kilometer.
What calculation will give us the estimated volume of fuel that remains in Carson's tank by the end of the drive, in liters?
Answer:
Step-by-step explanation:
The formula for the remaining volume of fuel in a car's tank is expressed as;
V = I - E.D
where;
I is the initial volume of fuel,
E is the fuel efficiency, and;
D is the distance traveled.
Given
I = 30 litres
1m³ = 1000L
x = 30L
x = 30/1000
x = 0.03m³
I = 0.03m³
E = 100cm³/km
E = 100*10^-6m³/km
E = 10^-4m³/km
E = 10^-4m³/1000m
E = 10^-7m²
D = 120km
Convert km to metres
D = 120km = 120,000m
Substitute the results into the formula;
V = I - E.D
V = 0.03 - (10^-7)(120,000)
V = 0.03 - 0.012
V= 0.018 m³
Convert 0.018 m³ to litres
Since 1 m³ = 1000L
0.018 m³ = y
cross multiply;
y = 1000 * 0.018
y = 18 litres
Hence volume of fuel that remains in Carson's tank by the end of the drive is 18 litres
4m^2-1=-23