Answer:
V₂=1.76 m³
P=222.03 KPa
Explanation:
Given that
For tank 1
V₁=1 m³
T₁= 10°C = 283 K
P₁=350 KPa
For tank 2
m₂=3 kg
T₂=35°C = 308 K
P₂=150 KPa
We know that for air
P V = m R T
P=pressure ,V= Volume,R= gas constant ,T= temperature ,m =mass
for tank 2
P₂ V₂ = m₂ R T₂
By putting the values
150 x V₂ = 3 x 0.287 x 308
V₂=1.76 m³
Final mass = m₁+m₂
m =m₁+m₂
The final volume V= V₂+V₁
V= 1.76 + 1 m³
V= 2.76 m³
The final temperature T= 19.5°C
T= 292.5 K
m =m₁+m₂
m =4.3 + 3 = 7.3 kg
Now at final state
P V = m R T
P x 2.76 = 7.3 x 0.287 x 292.5
P=222.03 KPa
B. Determine the overall heat transfer coefficients, U; and U., for the pipe.
C. Would your answer change if the two materials were swapped so that the inside material were carbon steel and the outside material of the pipe were made of AISI 304 stainless steel? If so, calculate new values for UA and q. If not, explain why your answer would not change. (Here, assume the dimensions of the inner material (now plain carbon steel) match those of the AISI 304 schedule 30 stainless steel from part A, and the stainless steel is 0.075 inches thick on the outside.)
Sorry man i dont know the answer to this one
Answer: Tl = - 13.3°C
the lowest outdoor temperature is - 13.3°C
Explanation:
Given that;
Temperature of Th = 21°C = 21 + 273 = 294 K
the rate at which heat lost is Qh = 5400 kJ/h°C
the power input to heat pump Wnet = 6 kw
The COP of a reversible heat pump depends on the temperature limits in the cycle only, and is determined by;
COPhp = Th/(Th - Tl)
COPhp = Qh/Wnet
Qh/Wnet = Th/(Th -Tl)
the amount of heat loss is expressed as
Qh = 5400/3600(294 - Tl)
the temperature of sink
( 5400/3600(294 - Tl)) / 6 = 294 / ( 294 - Tl)
now solving the equation
Tl = 259.7 - 273
Tl = - 13.3°C
so the lowest outdoor temperature is - 13.3°C
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
//declare arrays
string ItemName[100];
double ItemCost[100]={0.0};
//declare variable
string name="";
double Total=0.0;
int NumItems=0;
cout<<"Enter number of grocery item you will be entering";
cin>>NumItems
cout<<"\n";
if (NumItems>100)
{
cout<<"Enter grocery items less than 100"
cin>>NumItems
cout<<"\n";
}
for (int i=1;i>=NumItems;i++)
{
cout<<"Please enter the item name in one word only, Example: icecream\n";
cin>>ItemName[i]
cout<<"Please enter the cost as a decimal number, Example: 2.05\n\n";
cin>>ItemCost[i];
}
cout<<"Items"<<" "<<""$""<<"Cost"<<endl
for (int i=1;i>=NumItems;i++)
{
cout<<ItemName[i]<<" "<<"$"<<ItemCost[i]<<endl
}
for (int i=1;i>=NumItems;i++)
{
Total=Total+ItemCost[i];
}
cout<<"Total:$"<<Total<<endl;
system("PAUSE");
return 0;
}
Explanation:
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Answer:
Explanation:
mole fraction of propane after passing through the separator is
mole fractions of ethane and methane
after passing through separator are:
Change in partial pressures then can be written as:
where
and
are mole fractions after and before passing through the separator
Hence,