Answer:
50th term is 159
Step-by-step explanation:
nth term=159
a + (n -1)*d = 159
12 + (n-1)*3= 159
(n - 1)*3 = 159 - 12
(n - 1)*3 = 147
n -1 = 147/3
n - 1 = 49
n = 49 + 1
n= 50
Answer: n=50th term
Step-by-step explanation:
An= a1+(n-1)d
An= nth term
A1= first term
N= nth position
D= common difference
An =159
A1= 12
D= 3
N= ?
Substitute the values
An=a1+(n-1)d
159=12+(n-1)3
Collect like terms
159-12=(n-1)3
147=3n-3
147+3=3n
150=3n
N=150/3
N= 50
Therefore 50th term will give 156
The solution is : the least common denominator of 3/10 and 4/5 is 20.
The least common denominator is the smallest number of all the common multiples of the denominators when 2 or more fractions are given.
here, we have,
Let's list some multiples of each denominator
5: 5, 10, 15, 20, 25, 30
and,
10: 10, 20, 30, 40, 50, 60
and,
4: 4, 8, 12, 16, 20, 24, 28
so, we get,
The common denominator (LCD) is 20
So lets input
6/20, 20/20
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