MATHEMATICS MIDDLE SCHOOL

What is the value of t in the equation t−35=-15?

Answers

Answer 1
Answer:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     t/15-t/35-(1/15)=0 

Step by step solution :Step  1  : 1 Simplify —— 15 Advertising SkipEquation at the end of step  1  : t t 1 (—— - ——) - —— = 0 15 35 15 Step  2  : t Simplify —— 35 Equation at the end of step  2  : t t 1 (—— - ——) - —— = 0 15 35 15 Step  3  : t Simplify —— 15 Equation at the end of step  3  : t t 1 (—— - ——) - —— = 0 15 35 15 Step  4  :Calculating the Least Common Multiple :

 4.1    Find the Least Common Multiple 

      The left denominator is :       15 

      The right denominator is :       35 

        Number of times each prime factor
        appears in the factorization of: Prime 
 Factor  Left 
 Denominator  Right 
 Denominator  L.C.M = Max 
 {Left,Right} 310151117011 Product of all 
 Prime Factors 1535105


      Least Common Multiple: 
      105 

Calculating Multipliers :

 4.2    Calculate multipliers for the two fractions 


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 7

   Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

 4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well. 

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier.

L. Mult. • L. Num. t • 7 —————————————————— = ————— L.C.M 105 R. Mult. • R. Num. t • 3 —————————————————— = ————— L.C.M 105 Adding fractions that have a common denominator :

 4.4       Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

t • 7 - (t • 3) 4t ——————————————— = ——— 105 105 Equation at the end of step  4  : 4t 1 ——— - —— = 0 105 15 Step  5  :Calculating the Least Common Multiple :

 5.1    Find the Least Common Multiple 

      The left denominator is :       105 

      The right denominator is :       15 

        Number of times each prime factor
        appears in the factorization of: Prime 
 Factor  Left 
 Denominator  Right 
 Denominator  L.C.M = Max 
 {Left,Right} 311151117101 Product of all 
 Prime Factors 10515105


      Least Common Multiple: 
      105 

Calculating Multipliers :

 5.2    Calculate multipliers for the two fractions 


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

 5.3      Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num. 4t —————————————————— = ——— L.C.M 105 R. Mult. • R. Num. 7 —————————————————— = ——— L.C.M 105 Adding fractions that have a common denominator :

 5.4       Adding up the two equivalent fractions 

4t - (7) 4t - 7 ———————— = —————— 105 105 Equation at the end of step  5  : 4t - 7 —————— = 0 105 Step  6  :When a fraction equals zero : 6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4t-7 ———— • 105 = 0 • 105 105

Now, on the left hand side, the  105  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   4t-7  = 0

Solving a Single Variable Equation :

 6.2      Solve  :    4t-7 = 0 

 Add  7  to both sides of the equation : 
                      4t = 7 
Divide both sides of the equation by 4:
                     t = 7/4 = 1.750 

Related Questions

The volume of the rectangular prism is 240 cubic centimeters. A rectangular pyramid has the same length, width,and height as a prism.What is the volume of the pyramid?
Can someone help me with this? :)
Fiecare dintre cei 26 de baieti si 14 fete care au participat la excursia de la Bran au adunat câte 5 pietricele pentru acvariul clasei.Cate pietricele sunt in total?Calculează în două moduri.
Other ways to write 18:4
How many groups of 8 in 80?

Help fill out the proof

Answers

Answer:

Step V: Transitive property of Inequality

Step VI: Subtraction Property of Inequality

Step-by-step explanation:

In Step IV, the RHS of t=both the sides are equal.

So, they equated the LHS of both the sides.

This is the transitive property of equality which states that if a = b and c = b then a = c.

In this case, a = $ \angle {m_1} + \angle {m_2}  $

b = 180⁰

c = $ \angle {m_2} + \angle {m_3} $

Consequently, $ \angle {m_1} + \angle {m_2} = \angle {m_2} + \angle {m_3} $

In step VI, $ \angle {m_2} $ is subtracted on both the sides. So, this is called as Subtraction Property of Equality.

I don't know what the answer is

Answers

Hint:  Subtract 38 from both sides of this inequality.  This will simplify the inequality.   

Next, divide each side of your resulting inequality by 18.  This will produce an inequality of the form "x≤ something."

I am unsure of how to configure those tiles to represent this result.

What is .62 as a fraction in simple terms

Answers

31/50 is in simplest form 
31
___      or 31/50
50   
   use the calculator type .6.2 then = then press  F  < D ( fraction to decimal) 

Rob and Mike are on a club swimming team.They are training for a statewide swimming meet that will be held in the end of summer. The table shows how many hours Rob and Mike spent at practice each week

practice time (in hours). | Swimmer|weekly|Monday-Friday|
Rob. | 35. | 25 Mike. | 30. | 20 Question: write a possible expression to show how many hours Rob and Mike spend at swim practice over a period of 10 weekends . include parentheses and brackets in your expression.


Please help
and thank you

Answers

Mike: 20+30/2= 25 on average 
25*10=250 hours. 

Rob: 35+25/2=30 on average 
30*10=300 hours. 

Attribute that makes a square a special rectangle

Answers

rectangle is paralellogram with 4 right angles

squar is a rectangle with all equal sides (4 right angles and 4 side equal)
a rectangle has 4 sides  2 sides the saim 2 sides ither longer or shorter 

What is 1 3/4 ÷ 8? What does it equal?

Answers

it would be 14 because you would make 1 3/4 and split them up into 8s
Other Questions
PLEASE ANSWER QUIC, forget the answer I put
It doesnt show for me
Divide mentally.1.2 ÷ 3,000 = ?
Can someone help me please