MATHEMATICS HIGH SCHOOL

What is 8P3?A.
6720

B.
120

C.
336

D.
24

Answers

Answer 1

Answer:

The value of 8P3 is 336, so the correct option is option C. 336

How did we get the value?

To find the value of 8P3, we use the permutationformula, which is calculated as:

nPk = n! / (n - k)!

In this case, n is 8 and k is 3. So, we can substitute these values into the formula:

8P3 = 8! / (8 - 3)!

= 8! / 5!

= (8 × 7 × 6 × 5!) / 5!

Simplifying further:

8P3 = 8 × 7 × 6

= 336

Therefore, the value of 8P3 is 336, so the correct option is C.

learn more about permutation formula: brainly.com/question/1216161

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Answer 2

Answer: 8p3 = 336 hope this helps

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W(-3)=-3+7Find W(-3)=
If x=3 and y=-2 and z=4, what is the value of 3x + 2y - z?

Which shows a correct order to solve this story problem? Gina used 3.2 ounces of strawberry jelly and 4.7 ounces of raspberry jelly in her recipe. She made the same recipe 4 times.

How much jelly did Gina use altogether?

A.
Step 1: Add the weights of the two jellies.
Step 2: Divide that sum by 4.

B.
Step 1: Subtract the weight of the strawberry jelly from the raspberry jelly.
Step 2: Multiply that difference by 4.

C.
Step 1: Add the weights of the two jellies.
Step 2: Multiply that sum by 4.

D.
Step 1: Subtract the weight of the strawberry jelly from the raspberry jelly.
Step 2: Divide that difference by 4.

Answers

Answer is C

3.2 oz + 4.7oz = 7.9 oz * 4 = 31.6oz total

Ayana has 220 in her piggy bank. of those, 45% are pennies. how many coins are not pennies

Answers

220*45%=99
220-99=121
Answer; 121 coins are not pennies

well if she has 220 in her piggy bank then 100% of that number is 220 so 45% is a little under 50% it's going to be 55%. see how I did that?

07.04 Equilibrium: Hands-On Equilibrium Demonstration Lab Part III follows a similar procedure as Part I and Part II, except you will be adding additional candies to the activity. Start with 40 candies on the reactant side of the paper. For each round, half of the candies that were on the reactant (R) side of the paper from the last round should be moved to the product side. One-fourth of the candies that were on the product (P) side of the paper from the last round should be moved to the reactant side. (If you end up with a decimal for the number to exchange, round up.) At the end of each round, count the number of candies on each side of the paper and keep track of the numbers in a data table. After five rounds, add 40 more candies to the reactant side of the paper. Continue following the instructions in Step 2 with this new amount of candy (total of 80 pieces of candy) for an additional 10 rounds. At the end of 15 total rounds, calculate the ratio (ratio = P/R) of products to reactants.

Answers

0-40,0 1-20,20 2-15,25 3-13,27 4-13,27 5-13,27 6-13,27 7-13,27 8-13,27 9-13,27 10-13,27

Answer:

Part 1

40 0

20 20

25 15

12 28

19 21

9 31

17 23

8 32

16 24

8 32

Part 2: (has to be done at a number of your choice)

Part 3:

40 0

20 20

25 15

12 28

19 21

9 31

49 31

34 56

48 42

24 66

41 49

10 70

28 52

14 66

31 35

47 19

Step-by-step explanation:

There's the actual ratios :) Hope this helps someone!

This is so confusing please help

Answers

a^n * a^m=a^(n+m)

Then.
a⁴*a^x=a^(⁴+x)

Answer: A. 5^(⁴+x)

Which equation models the height, y, x seconds after firing?

Answers

i dont see any equations there

Two faucets are dripping. One faucet drips every 4 seconds and the other faucet drips every 9 seconds. If a drop of water falls from both faucets at the same time, how many seconds will it be before you see the faucets drip at the same time?

Answers

The time at which both the faucets drip at the same time is 36 seconds

What is Least Common Multiple?

Least Common Multiple (LCM) is a method to find the smallest common multiple between any two or more numbers. A common multiple is a number which is a multiple of two or more numbers

Given data ,

Let the time at which both faucet drips at the same time be = T

Let the first faucet be represented as = A

Let the second faucet be represented as = B

Now , the time at which the faucet A drips = 4 seconds

And , the time at which the faucet B drips = 9 seconds

So , the equation is given as

The time at which both faucets A and B drips at the same time = Least Common Multiple of both the times of faucet A and faucet B

Substituting the values in the equation , we get

The time at which both faucets A and B drips at the same time = Least common multiple of 4 and 9

Multiples of 4 = 4 , 8 , 12 , 16 , 20 , 24 , 28 , 32 , 36 , 40 ...

Multiples of 9 = 9 , 18 , 27 , 36 , 45 , 54 , 63 , 72 ...

So , 36 is the least common multiple of 4 and 9

Therefore , the value of T is 36 seconds

Hence ,

The time at which both the faucets drip at the same time is 36 seconds

To learn more about least common multiple click :

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