The statement that weather differs from climate in that weather can change on a daily basis and is not considered a description of year-to-year conditions of temperature and precipitation is true. While the climate pertains to the atmospheric conditions over long periods of time.
Answer: true
Explanation:
got it right on edge
Answer:
The hottest objects with temperatures in the millions of Kelvins, give off most of their radiation in the form of X-rays and gamma rays.
Explanation:
The electromagnetic (EM) spectrum contains radio waves, microwaves, infrared light, visible light, ultraviolet light, X-rays and gamma-rays. All these different types of radiation are made up of photons having specific wavelengths and different amounts of energy. In the EM spectrum, the photons of radio waves have the lowest energy and the energy of photons increases through microwaves, infrared, visible light, ultraviolet, X-rays, and the photons of gamma-rays have the highest energy (the energy of photons is measured in electron volts).
All warmer objects such as stars, planets, etc emit photons having a specific range of wavelengths and it depends on the surface temperature of those objects. The very hot objects with temperatures in the millions of Kelvins or more mainly emit photons with shorter wavelengths, such as gamma rays and X-rays while cooler objects emit radiation such as infrared or radio waves, having longer wavelengths.
The ultraviolet radiation has the energy in the range of a few electron volts to about 100 eV. The energy of X-ray photons is in the range of 100 eV to 100 keV and the energy of gamma-rays is greater than 100 keV. The nuclear explosions, radioactive decay, the hottest and most energetic objects in the universe such as neutron stars, supernova explosions, etc produce gamma rays.
Objects with temperatures in the millions of Kelvins emit most of their radiation in the X-ray and gamma-ray parts of the electromagnetic spectrum.
Objects with temperatures in the millions of Kelvins primarily give off most of their radiation in the X-ray and gamma-ray parts of the electromagnetic spectrum. As an object's temperature increases, the wavelengths of radiation it emits become shorter. This phenomenon is described by Wien's displacement law.
At lower temperatures, such as those found on Earth or in stars like our Sun, objects emit most of their radiation in the visible and infrared parts of the spectrum. However, as temperatures rise to millions of Kelvins, the emitted radiation shifts to shorter wavelengths, eventually falling into the X-ray and gamma-ray regions.
In the X-ray and gamma-ray parts of the electromagnetic spectrum, radiation has extremely high energy and short wavelengths. These types of radiation are associated with the very high temperatures and intense energy found in extremely hot objects, such as the cores of massive stars, supernovae, and certain high-energy astrophysical phenomena. Scientists use X-ray and gamma-ray telescopes to study these extreme environments and the radiation they emit.
Learn more about Electromagnetic Spectrum here:
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Answer:
1069.38 gallons
Explanation:
Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.
V₁ = V₀(1 + βΔθ) β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹
Δθ = (5/9)(97°F -52°F) °C = 25 °C.
Let V₂ be its final volume when it cools to 52°F in the tank is
V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)
= 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)
= 1.07 × 10³(1 - [0.024]²)
= 1.07 × 10³(1 - 0.000576)
= 1.07 × 10³(0.999424)
= 1069.38 gallons
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. Using the equation for volume expansion, we can calculate this change in volume to be approximately 258 gallons.
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. We can use the equation for volume expansion to calculate this change in volume:
ΔV = V₀ * β * ΔT
Where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
In this case, the initial volume V₀ is 1.07 * 10³ gallons, the coefficient of volume expansion β is 9.6 * 10⁻⁴ (°C)⁻¹, and the change in temperature ΔT is (52.0°F - 97.0°F) = -45.0°F.
Converting the change in temperature to Celsius: ΔT = (45.0°F) * (5/9) = -25.0°C.
Plugging in these values into the equation, we get:
ΔV = 1.07 * 10³ * 9.6 * 10⁻⁴ * -25.0 = -258 gallons.
Therefore, when the gasoline is poured into the tank, approximately 258 gallons will be poured out of the truck.
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Answer:
The answer is B.
Explanation:
Given that the current (Ampere) in a series circuit is same so we can ignore it. We can assume that the total voltage is 60V and all the 3 resistance are different, 20Ω, 40Ω and 60Ω. So first, we have to find the total resistance by adding :
Total resistance = 20Ω + 40Ω + 60Ω
=120Ω
Next, we have to find out that 1Ω is equal to how many voltage by dividing :
120Ω = 60V
1Ω = 60V ÷ 120
1Ω=0.5V
Lastly, we have to calculate the voltage at R1 so we have to multiply by 20 (R1) :
1Ω = 0.5V
20Ω = 0.5V × 20
20Ω = 10V
Answer:
height=2
Explanation:
MA= input/output
MA= 5
input = 10 (the ramp)
output=x (the height)
5=10/x
x=2
Answer:
1,803,036.67 W
Explanation:
Data provided in the question:
People per hour that can be moved by lift = 49800
Height of movement, h = 190 m
Average mass per person = 70 kg
Now,
Power = Rate of doing work
Thus,
Power = ΔU
= mgh
here,
m = total mass
g = acceleration due to gravity
or
Power = (70kg × 49800)(9.8)(190)
or
Power = 6,490,932,000 J per hour
also,
Watt = Joule/second
Therefore,
Power = 6,490,932,000 ÷ 3600
= 1803036.67 W
To estimate the maximum total power needed for Squaw Valley ski area to move 49800 people per hour on their lifts, we calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190 m. The estimated maximum total power needed is 3.31 x 10^8 W.
To estimate the maximum total power needed to move 49800 people per hour on a skilift at Squaw Valley, we can calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190m. The work done is equal to the potential energy gained, which is given by the formula mgh, where m is the average mass per person (70 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the vertical height gained (190 m). Multiplying this by the number of people per hour gives us the total work done per hour. Dividing this by the time taken to travel the vertical height gives us the maximum power needed. The power is given by the formula P = W/t, where W is the work done and t is the time taken.
Using the given values, we have:
Work done per person per hour: (70 kg) x (9.8 m/s^2) x (190 m) = 128660 J
Total work done per hour: 128660 J x 49800 = 6.40 x 10^9 J
Time taken to travel vertically by 190m: 190 m / (9.8 m/s^2) = 19.39 s
Maximum power needed: (6.40 x 10^9 J) / (19.39 s) = 3.31 x 10^8 W
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