Does the equation y= -1/x represent a direct or inverse variation?
Answers
The equation y = -1/x represent a inverse variation
Solution:
Given, equation is
We have to find the relation between x and y
Now, for finding the relation we have to take two sets of values of x and y and substitute them in given equation.
If we observe, when y value is decreased from 1 to – 1, the value of x is increased from -1 to 1
Hence, the x and y varies inversely
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On your birthday, you deposit $540.00 in a account that pays 6% interest, compounded annually. How much is in the account 3 years later?
Write a fraction with the denominator of 6 that is greater than 2/4.
4 sweets cost 28p altogether. how much do 7 sweets cost?
Answers
5 / 5 = 1
30 / 5 = 6
5/30 = 1/6
B. 9a^2-30a-25
C. 25b^2-15b +9
D. 16x^2-24x+9
Answers
Answer:
D
Step-by-step explanation:
16x^2 - 24x + 9
(4x - 3)^2
(4x - 3) (4x - 3)
16x^2 - 12x - 12x + 9
16x^2 - 24x + 9
Answers
72*100=7200
7200 divided by 45=160
Therefor the trip was 160 miles long
y=2/3x+3
y=__/__x+5
Answers
y=(z/t)x+5
so subsitute and solve
3/2x+3=(z/t)x+5
subtract 5 from both sides
3/2x-2=(z/t)x
divide both sides by x
3/2-2/x=z/t
so combine
3/2-2/x
3/2 times x/x-2/x times 2/2=3x/2x-4/2x=(3x-4)/2x
the values are (3x-4)/2x
Answers
Answer:
Step-by-step explanation:
it should be clear 2pi > 6.
Also, sqrt(35) < 6 because 6x6=36.
So, 2pi > 6 > sqrt(35)
Thus 2pi > sqrt(35)
:)
Answers
Each student worked on 115 math problems.
Step-by-step explanation:
Given,
Problems solved in 4 hours = 8970
Number of students in competition = 78
As each student solved same number of problems, we will divide the total problems solved by number of students to find the amount of problems solved by one student.
Problems solved by one student =
Problems solved by one student = 115
Each student worked on 115 math problems.
Keywords: division
Learn more about division at:
#LearnwithBrainly
Each student works 115 problems.
Explanation:
I'm going to copy and paste the question here, and bold important info.
"Rayville Elementary sponsors a math competition for 78 students. During the competition, the students work a total of 8,970 math problems in 4 hours. Each student works the same number of problems. How many problems does each student work?"
Now everything not bolded? Forget about it. All you need to know is that there are 78 students. They all do 8,970 # of problems. And all the students do the same amount. Now you just have to divide the # of probs. by the amount of students in the competition, and you have your answer.
8970÷78=115
Hope that helped!