A 1.7-kg block of wood rests on a rough surface. A 0.011-kg bullet strikes the block with a speed of 670 m/s and embeds itself. The bullet-block system slides forward 2.4 m before coming to rest.

Answers

Answer 1

Answer:

What is the coefficient of kinetic friction between the block and the surface? Express your answer using two significant figures.

Answer:

0.39

Explanation:

Given information

m1=1.7 Kg

m2=0.011 Kg

v2=670 m/s

d=2.4 m

m2v2=(m1+m2)v hence $v=\frac {m2v2}{m1+m2}$ and also $a=\frac {v^(2)}{2d}$

The deceleration due to friction is given by

$F=\mu_k N=\mu_k W=\mu_k (m1+m2)g$

$F=(m1+m2)a=\mu_k (m1+m2)g$ therefore $a=\mu_k g$

Therefore, $a=\frac {v^(2)}{2d}=\mu_k g$

$\mu_k=\frac {1}{2dg}(\frac {m2v}{m1+m2})^(2)=\frac {1}{2*2.4*9.81}* (\frac {0.011*670}{1.7+0.011})^(2)$

$\mu_k=0.39$

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A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3300 N and the mass of the truck is 1600 kg, what's the radius of the curve?

Answers

Well, first of all, the truck's velocity is constantly changing, not 'uniform'.
Velocity consists of speed and direction. So, even if the truck's speed is
constant, its direction keeps changing as long as it's on a circular curve,
so its velocity is constantly changing.

The force needed to keep a mass moving in a circle is

   F = (mass) x (speed)² / (radius)

   3300 N = (1600 kg) (13 m/s)² / R

   3300 kg-m/s² = (1600 kg) (169 m²/s²) / R

   R = (1600 kg) · (169 m²/s²) / (3300 kg·m/s²)

   = (1600 · 169 / 3300) meters

   = 81.9 meters

The Correct answer to this question for Penn Foster Students is: 81.94m

A mass of 2kg has a kinetic energy of 16J.what is the momentum of the body?

Answers

Explanation:

mass - 2kg

energy - 16 j

k.e- 1/2mv

16j=1/2×2×v

16×2/2=v

16=v

√16=v

V=4m/s

then momentum =mv

= 2×4

= 8 kgm/s

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The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Answers

Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

$g_(1)$ = GM/r² (i)

$g_(1)$ = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

$g_(2)$ = GM/(2r)²

$g_(2)$ = GM/4r²

$g_(2)$ = GM/r² *1/4

from (i)

$g_(2)$ = $g_(1)$ *1/4

$g_(2)$ = 15/4

$g_(2)$ = 3.75m/s²

A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force acting on the charge?

Answers

ok
here is your anwer
O hope it is useful for you

Answer:

2.7N

Explanation:

Extend the life of your __________ by avoiding fast starts, stops and sharp turns.(A) ignition
(B) exhaust
(C) oil filter
(D) tires

Answers

Answer:

Tires.

Explanation:

There are the few steps which are discussed below should be taken to increase or extend the life of tires.

(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.

Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.

Final answer:

The life of tires can be extended by avoiding fast starts, stops and sharp turns. These maneuvers cause excessive friction which leads to quicker deterioration. Suitable driving habits can extend the life of the tires.

Explanation:

You can extend the life of your tires by avoiding fast starts, stops, and sharp turns. When a driver performs a fast start, a large amount of friction is produced between the tires and the road, causing the tires to wear faster. The same goes for abrupt stops and sharp turns, which also produce an excess amount of friction, leading to a quicker deterioration of the tires.

Therefore, to extend the life of your tires, it is advisable to drive in a cautious and considerate manner, avoiding fast starts and stops and refraining from making sharp turns whenever possible.

Learn more about Tire Lifespan here:

brainly.com/question/32437276

#SPJ3

1. The photon energy for light of wavelength 500 nm is approximately (Show your work).1.77 eV
3.10 eV
6.20 eV
2.48 eV
5.46 eV

2. Which of the following colors is associated with the lowest temperature? Explain your reasoning.
A. Blue
B. Green
C. Yellow
D. Red

3. Which of the following colors has the highest photon energy?
A. Blue
B. Green
C. Yellow
D. Red
Explain your reasoning.

Answers

1)
E=hf=h*c/α
E=6.626*10^-34*3*10^8E=

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Suppose you decide to cut the wire into two pieces (not necessarily the same length) to shape into two circles. Write a function A ( x ) which models the total area of the two circles in terms of x , the length of one of the pieces of wire. (It may be helpful to use for a circle A = πr 2 and C = 2 πr ). Then find the length x that will minimize the total area.