B.a moving rod
C.a magnetic field
D.electrical energy
Answer:
eletrical ENERGY
Explanation:
D.
whats the magnitude in N ?
(b) Find the centripetal acceleration of the electron.
whats the magnitude in m/s2
Answer:
L' = 555.95 lb
Explanation:
Analyzing the given conditions in the question, we get
The safe load, L is directly proportional to width (w) and square of depth (d²)
also,
L is inversely proportional length (l) i.e L = k/l
combining the above conditions, we get an equation as:
L = k(wd²/l)
now, for the first case we have been given
w = 3 in
d = 6 in
l = 11 ft
L = 1213 lbs
thus,
1213 lb = k ((3 × 6²)/11)
or
k = 123.54 lbs/(ft.in³)
Now,
Using the calculated value of k to calculate the value of L in the second case
in the second case, we have
w = 6 in
d =3 in
l = 12 ft
Final Safe load L' = 123.54 × (6 × 3²/12)
or
L' = 555.95 lb
The load that a beam of the given dimensions can support is derived using a joint variation formula. The constant of variaiton is found using the given beam's characteristics, and then applied on the second beam's measurements to find its load. The result is approximately 2025 pounds.
The question is related to joint variation and its principles in mathematics. First, it's necessary to define the equation of the joint variation:
L = k*(w*d^2)/l
where L is the load, w is the width, d is the depth, l is the length, and k is the constant of proportionality. From the information given in the question, we can derive that k equals to 1213 * 11 / (3 * 6^2), which is approximately 135. Then, we substitue the values of the second beam into the equation, w = 6, d = 3, l = 12 and k = 135, to get the load L for the second beam, which equates to about 2025 pounds.
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Answer:
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