Solve mathematics problem in photo please! :) First.
Solve mathematics problem in photo please! :) First. - 1

Answers

Answer 1
Answer: Hello,

Answer B

if 3k+3<0 ==>|3k+3|=-3k-3

==>-3k-3>12
==>-3k>15
==>k<-5

if 3k+3>0 then |3k+3|=3k+3
3k+3>12
==>3k>9
==>k>3


Related Questions

During the first week of the year, Angelina's dad give her $10 and says that he will give her $10 more each week for the rest of the year. At the end of the year, how much money will Angelina receive from her dad? (Hint : 1 year = 52 weeks) Make a table to show the pattern, and explain your answer.
Show that (4-√3)(4+√3)/√13 simplifies to root 13
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Jeremy wants to buy a new computer. The saleswoman says that he can make a down payment and then pay for the computer in installments.Here's a formula that describes this scenario: x=t-yz x = Amount down y = Money each month z = Number of months t = Total price Rewrite the formula to solve for the amount of money Jeremy must pay each month.
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Lisa is seven times as old as her brother. She will be four times as old as her brother in three years. Represent the above situation in mathematical form.

Answers

Answer:

Let B = the brothers age now

Let L = Lisa's age now

 

Then today:

 

L = 7B

 

And three years from now, Lisa's current age plus 3 equals 4 times the brothers age plus 3 represented by the following formula

 

L+3 = 4(B+3)

 

Now we can substitute the value of L in the first formula for L in the second formula

 

7B + 3 = 4(B+3)

 

So the answer is C

Step-by-step explanation:

2. You spin a spinner that has eight equal-sized sections numbered one to eight. Which event isleast likely to occur?
The number is even.
The number is less than three.
The number is greater than three.
The number is a multiple of five.

Answers

Answer:

Getting a multiple of 5 is the least likely outcome.

Step-by-step explanation:

We spin a spinner that has 8 equal-sized sections numbered 1 - 8.

We have to find which is the least likely to occur.

The number is even when outcomes are 2,4,6 or 8.

Number of outcomes = 4

If the number is less than 3, the number of possible outcomes are 2 that is 1 and 2.

If the number is greater than 3 , number of possible outcomes is 5 which are 4,5,6,7 and 8.

If the number is a multiple of 5, only 1 outcome is there which is 5 itself.

Hence getting a multiple of 5 is the least likely outcome.

Students have a grace period of ______ before they must begin repaying Direct Stafford Loans.A. 12 months
B. 3 months
C. 1 month
D. 6 months

Answers

D. 6. months. This can be extended for a further three years, however.

Answer: The answer is D) 6 months

APEX

Recall the symbol Z represents the complex conjugate of z. If z=a+bi and w=c+di show that the statement is true zw=z*w

Answers

z = a + bi
w = c + di

zw = (a + bi)(c + di)
zw = a(c + di) + bi(c + di)
zw = a(c) + a(di) + bi(c) + bi(di)
zw = ac + adi + bci + bdi²
zw = ac + adi + bci + bd(-1)
zw = ac + adi + bci - bd

50 points if you answer correctly

Answers

Answer:

f(3) =  {3}^(2)  + 5(3) - 9 \n f(3) = 9 + 15 - 9 \n f(3) = 15

Answer:

1. D. 15

2. A. 3

3. A. c= 6g+5

4. A. All real numbers

5. D

                                         

                                     

Here is another for fun question. MUST SHOW ALL WORKINGSSo,
What is the biggest 4 digit whole number that meets the three requirements

1. the digits are different
2. the largest digit is equal to all of the other 3 digits added together
3. if you multiply the digits with each other, the result is evenly divisble by 10 with no remainders and is not equal to zero

also do not copy

Answers

For the product of the digits to be divisible by 10, it must have 10 as a factor, of course. Since 10 can't act as a digit, this means two of our digits must be 2 & 5.

No digit can be 0 because this would give a total product of 0.

Neither 2 nor 5 can be our largest because the lowest you can get is 1+2+3=6.
The lowest possible largest digit would have to be 1+2+5=8.
As for 9, this is not an option, and here's why: We need that 2 and 5, but to get 9 our other digit would have to be 2, which is a repeat.

So, our digits are 1, 2, 5, and 8.
It doesn't matter which order they are in. (take a look at the rules)
Therefore, we should put the highest digits in the highest value places.

The answer is \boxed{8521}