MATHEMATICS HIGH SCHOOL

Jeremy wants to buy a new computer. The saleswoman says that he can make a down payment and then pay for the computer in installments.Here's a formula that describes this scenario:

x=t-yz

x = Amount down
y = Money each month
z = Number of months
t = Total price

Rewrite the formula to solve for the amount of money Jeremy must pay each month.

Answers

Answer 1

Answer:

Answer: $y=(t-x)/(z)$

Step-by-step explanation:

Given: A formula that describes this scenario:

$x=t-yz$

where, x = Amount down

y = Money each month

z = Number of months

t = Total price

To solve the formula for the amount of money Jeremy must pay each month i.e. y, first subtract t on both sides of the equation, we get,

$x-t=-yz\n\n\Rightarrow\ yz=t-x$

Now, divide z on both sides, we get

$y=(t-x)/(z)$

Answer 2

Answer:

The correct answer is:

$y=(-x+t)/(z)$

Explanation:

We want to solve for the amount of money he pays each month. This is represented by y in the equation. This means we want to isolate y in the equation:

x = t - yz

We first want to subtract t from each side:

x - t = t - yz - t

x - t = -yz

Now we want to cancel the negative sign and z. We can isolate both of these at the same time; divide both sides by -z:

We can divide the numerator by the negative sign; this gives us

$(-x+t)/(z)=y$

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$(6x)^2=36x^2$

(Apparently this needs 20 characters to explain it will, so have this type.)
(6x)^2 = 36x^2
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What is if g(x,y,z) = x + y and S is the first octant portion of the plane 2x + 3y + z = 6 ?

Answers

The question asks for the value of $I=\int\int_Sx+y\textrm{ }dS$ where $S=\{(x,y,z)\mid2x+3z+y=6,x\ge0,y\ge0,z\ge0\}$ .

First let's look at what that surface looks like.

Letting $y=z=0$ yields $x=3$
Letting $x=z=0$ yields $y=2$
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$I=\int_(z=0)^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_(x=0)^(6-z)dz=\int_(z=0)^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz$

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Hence $\boxed{I=\int\int_Sx+y\textrm{ }dS=36}$

at a lunch stand, each hamburger has 50 more calories than each order of fries. if 2 hamburgers and 3 orders of fries have a total of 1700 calories, how many calories does a hamburger have?

Answers

The correct answer is 370. A system of equations can be used, where h represents the number of calories in a hamburger and f represents the number of calories in an order of fries. The equation 2 h plus 3 f equals 1,700 represents the fact that 2 hamburgers and 3 orders of fries contain a total of 1700 calories, and the equation h equals f plus 50 represents the fact that one hamburger contains 50 more calories than an order of fries. Substituting f plus 50 for h in 2 h plus 3 f equals 1,700 gives 2, parenthesis, f plus 50, close parenthesis, plus 3 f, equals 1,700. This equation can be solved as follows:

2 f plus 100 plus 3 f equals 1,700

5 f plus 100 equals 1,700

5 f equals 1,600

f equals 320

The number of calories in an order of fries is 320, so the number of calories in a hamburger is 50 more than 320, or 370.

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Answers

464 ft
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Answers

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Answers

bd = 1/2 ae
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