Which of the following functions has the largest value when x = 4?e(x) = x2 + 6x + 21
m(x) = 8x
v(x) = 31x

Answers

Answer 1
Answer:

Answer: v(x)=31x


Step-by-step explanation:

Given Functions: e(x)=x^2+6x+21

m(x)=8x\n\nv(x)=31x

At x=4

e(4)=(4)^2+6(4)+21\n=16+24+21=61\n\nm(4)=8(4)=32\n\nv(4)=31(4)=124

here we can see v(4) has the largest value of 124 at x=4 .

Therefore, v(x)=31x is the function which has the largest value at x=4.

Answer 2
Answer: e(4)=4^2+6 * 4+21=16+24+21=61 \n \nm(4)=8 * 4=32 \n \nv(4)=31 * 4=124

v(x) has the largest value when x=4.

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Answers

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Answers

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Answers

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B.
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Answers

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Answers

Answer:

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Answers

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