For which equation is m = 12 not the solution?15 - m = 3
m + 8 = 20
m - 3 = 15
2 + m = 14

Answers

Answer 1
Answer: Hello,

Answer C for

m-3=15
==>m=15+3
==>m=18


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PLEASE HELP WILL GIVE BRAINIEST1. Which is the equation of the given line in ponit-slope form?A. y + 4 = 9/8(x + 1)B. y + 1 = 8/9(x + 4)C. y + 1 = 8/7(x + 4)y - 1 = 8/9(x - 4)(SAME IMAGE FOR QUESTION 2)2. Write the equation of the line in standard form. A. -8x + 9y = 23B. -8x + 9y = -23 C. -8x + 7y = 25D. -9x + 8y = -23

A group of students is taking a CPR course. The total cost for the course is $275. The room in which the course will be held can hold a maximum of 25 people, including the instructor. What is the minimum number of students needed to take the course so that the cost per student will be less than $15? A. 11 B. 17 C. 18 D. 19

Answers

25 people = 24 students + 1 instructor;
$275 / x < $15
x > $275 : $15
x > 18.3333
x = 19
Answer: 
The minimum number of students is: D ) 19.

Answer:

The answer is the option D

the minimum number of students will be 19

Step-by-step explanation:

Let

x-------> the minimum number of students

we know that

15x\geq 275 ------> inequality that represent the situation

The domain of the inequality is the interval-------> [0,24]

Solve for x

Divide by 15 both sides

x\geq 275/15\n x\geq 18.33

so

the minimum number of students will be 19

At what point (x,y) do the two lines with equations x-2y=5 and 3x-5y=8 intersect?

Answers

\begin{cases} x-2y=5 \ \ /*(-3)\n 3x-5y=8 \end{cases}\n \n\begin{cases} -3x+6y=-15 \n 3x-5y=8 \end{cases}\n + \ -------\n y=-7\n \nx-2y=5 \n \nx-2*(-7)=5 \n \nx+14=5 \ \ |-14\n \nx=5-14 \n \nx=-9 \n \n \begin{cases}x=-9 \n y=-7 \end{cases} \n \n \nAnswer: \ \ this \ is \ the \ point : \ \ (-9,-7)

Diego runs for 32 seconds at -8.1 meters per second. What is his finish point?

Answers

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What is the correct order of operations for simplifying the expression (x+3)^2-(x^2+9)/2x^2

Answers

Answer with explanation:

The correct order of simplifying the expression is:

1. Opening the bracket Using Identity

2. Adding and Subtracting Like terms

The given expression is

=((x+3)^2-(x^2+9))/(2x^2)\n\n=(x^2+6 x+9-x^2-9)/(2x^2)\n\n=(6x)/(2x^2)\n\n=(3)/(x)\n\n \text{Used the identity and law of indices}\n\n(a+b)^2=a^2+2 a b+b^2\n\n (x^a)/(x^b)=x^(a-b)

((x+3)^2-(x^2+9))/(2x^2)\n\nuse\ (a+b)^2=a^2+2ab+b^2\n\n=(x^2+2\cdot x\cdot3+3^2-x^2-9)/(2x^2)=(x^2-x^2+6x+9-9)/(2x^2)\n\n=(6x)/(2x^2)=(3)/(x)

Sheena declared bankruptcy. How long will that fact remain on her credit report?A.
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B.
up to 10 years

C.
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D.
2 years or less

Answers

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4 fifths take away 1 half

Answers

The picture shows you have to find the least common multiple of both the denominator. Change the numerators accordingly and subtract normally.