Simultaneous Linear Equations could be solved by using several methods such as :
If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.
Let us tackle the problem!
Let :
Number of Fred's Flowers = f
Number of Ethyl's Flowers = e
Fred and ethyl had 132 flowers altogether at first.
→ Equation 1
After Fred sold 1/4 of his flowers and Ethyl sold 48 of her flowers, they had the same number of flowers left.
← Equation 1
Grade: High School
Subject: Mathematics
Chapter: Simultaneous Linear Equations
Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations
Slope Form
Distance Formula
Quadratic Formula
The blanket is 2.25 meters long and 1.8 meters wide
Blanket will be in the shape of rectangle
Area of rectangle formula is Length * width
Given : Length = 2.25 meters
width = 1.8 meter
Area = Length * width
= 2.25 * 1.8 = 4.05
so the area of the blanket = 4.05 square meters
We need to convert the answer in centimeters
1 meter = 100 cm
4.05 meters = 4.05 * 100 = 405 square cm
the area of the blanket = 405 square cm
The blanket's area is 40,500 cm²
Further Explanation
The blanket length is 2.25 m
width is 1.8 m
The blanket usually in rectangular shape, so to calculate the area of the blanket would be:
so the blanket's area is 4.05 m²
Here is how to do decimal numbers multiplication:
2.25 ⇒ 2 decimal place
1.8 x ⇒ 1 decimal place
1800
235 +
4.050 ⇒ 3 decimal place
to multiply decimal numbers, it is the same process as multiply the whole numbers, except the decimal place position. In the calculation above:
the first factor has 2 decimal place
the second factor has 1 decimal place
so the result will have 3 decimal place (2+1)
Back to the question, after we find out the blanket's area in meters, let's convert it to centimeters
so
The blanket's area is 40,500 cm²
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Keywords: conversion, converting, unit of length, metric system of measurement, meter square to centimeter square, unit conversion, decimal numbers multiplication, additional, multiplication
To know that Alex did not have more than 800 coins exactly.Alex had 421 coins.
Well, we know that however many coins he does have, x, is not more than 800 AND cannot be divided by 2, 3, 4, 5, 6, or 7.
So,we need to find a number that can divide into 800 but the rest cannot.
x mod 3=1, x mod 4= 1, x mod 5 = 1 and x mod 7 =1.
Note that if x mod 3 =1 and x mod 4 =1 then x must be of the form 12a+1. So (12a+1) mod 2= 1
Counting is the process of determining the number of elements of a finite set of objects, i.e., determining the size of a set.
(12a+1) mod 6 =1.
That is you need not have the equations for 2 and 6.
To satisfy the 4 equations above x must be of the form
(3*4*5*7)b+1 =420b+1.
Knowing that x <800 we get that b=1 and so x=421.
Therefore Alex had 421 coins.
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