MATHEMATICS MIDDLE SCHOOL

Show all work and provide necessary descriptions

Answers

Answer 1

Answer:

Let

$P=(P_x,P_y),\quad Q=(Q_x,Q_y)$

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

$M=\left((P_x+Q_x)/(2),\ (P_y+Q_y)/(2)\right)$

We can solve this expression for the coordinates of Q:

$M_x = (P_x+Q_x)/(2) \implies Q_x = 2M_x-P_x$

$M_y = (P_y+Q_y)/(2) \implies Q_y = 2M_y-P_y$

Plug in the values for the coordinates of M and P to get

$Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1$

$Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6$

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Carlolyn determines that the area of a white triangle is half the area of a shaded triangle because the ratio of the side lengths of a white triangle to a shaded triangle is 3/6. Is Carolyn correct?Explain. What is the ratio of the area of the shaded pieces to the area of the white pieces? Show your work

Find three consecutive even integers whose sum is -132

Answers

Answer:

The consecutive even numbers are -42, -44, -46

Step-by-step explanation:

As the numbers are consecutive even integers,

Let,

The first number is "x"

The second number is "x+2"

The third number is "x+4"

According to the equation,

x + (x+2) + (x+4) = -132

As the sum is -132. Now we break the parenthesis by using the addition rule.

or, x + x + 2 + x + 4 = -132

or, 3x + 6 = -132

or, 3x = -132 - 6 (side change)

or, 3x = -138

or, x = -138/3 (interchange)

or, x = -46

Therefore, the first number is -46

The second number is -46+2 = -44

And the third number is -46+4 = -42

The consecutive even numbers are -42, -44, -46

Need helpp fastt plss will give brainliest to who is correct plss helpp

Answers

I think I might have my math wrong here but I think 5

Solve the following equation, answer as a reduced, mixed number. Then place the correct number in the box provided. 4(2x -3) + 8(x - 4) = 2(2x + 6

Answers

Answer:

4 2/3

Step-by-step explanation:

4(2x -3) + 8(x - 4) = 2(2x + 6)

Distribute

8x -12 + 8x -32 = 4x +12

Combine like terms

16x - 44 = 4x+12

Subtract 4x from each side

16x-4x-44 =4x-4x+12

12x-44 = 12

Add 44 to each side

12x-44+44 = 12+44

12x = 56

Divide each side by 12

12x/12 = 56/12

x = 14 / 3

Changing to a mixed number

x = 4 2/3

Nina's garden is 4 1/5 meters long and 3/10 meter wide. what is the area of nina's garden

Answers

Area of rectangular garden = 21/5 $*$ 3/10 = 63/50 =1 $* \n$ 13/50 $m^(2)$ = 1.26 $m^(2)$

Consider Nina' s Garden is rectangular in shape

Length of the garden = 4 $*$ 1/5 = 21/5

Width of the garden = 3/10

Area of the rectangle is given by

Area = Length $*$ Width

So the area of the garden is given by

Area= 21/5 $*$ 3/10 = 63/50 =1 $* \n$ 13/50 $m^(2)$ = 1.26 $m^(2)$

For more information please refer to the link

brainly.com/question/24408520

Area= length * width

length = 4 1/5= 21/5 . Multiply the whole number with the denominator. 4*5= 20 . Add 20 with the numerator. 20+1=22

width= 3/10

21/5* 3/10 ( Multiply the denominators together). ( Multiply the numerators together).

21*3 / 5*10

= 63/50 meters^2 or in mixed number:1 13/50 meters^2

Answer : 63/50 meters^2 or in mixed number:1 13/50 meters^2

25 PTS!!!!y = 3x + 3 y = x − 1 Explain how you will solve the pair of equations by substitution. Show all the steps and write the solution in (x, y) form

Answers

remember that you can do anything to an equaiton as long as you do it to both sides
ok so subsitution
basiclalyy you subsitute a known thing for an unknown thing so
y=3x+3 and y=x-1
they both equal y so
3x+3=y=x-1
3x+3=x-1
subtract x from both sides
2x+3=-1
subtract 3 from bot sides
2x=-4
divide both sides by 2
x=-2
subsitute
y=x-1
y=-2-1
y=-3

the solution is x=-2 y=-3 so
(x,y)
(-2,-3)

A club is going to raise money by printing calendars with photos of the community. The cost of printing the calendars is $5.50 per calendar. The photographer also charges a one-time cost of $200 for taking the photos. The club has $1500 to cover the initial costs of the calendar. Create an equation that represents the number of calendars the club can print. Use the variable n for the number of calendars (You do not need to solve the equation).

Answers

Answer:

The total cost to print n calendars is the sum of the cost of printing each calendar and the one-time cost for taking the photos:

Total cost = (Cost per calendar * Number of calendars) + One-time cost for photos

Given that the cost per calendar is $5.50 and the one-time cost for photos is $200, the equation can be written as:

Total cost = 5.50n + 200

Now, we know that the club has $1500 to cover the initial costs of the calendars. Therefore, the equation can be set equal to $1500:

5.50n + 200 = 1500

So, the equation representing the number of calendars the club can print is 5.50n + 200 = 1500, where n is the number of calendars.

Step-by-step explanation:

1500 so yes its the easy way

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