For the number 3.48 we have:
We multiply and divide the number by 100:
We simplify the fraction obtained.
Answer:
3.48 repeating as a fraction is:
For the number 1.07 we have:
We multiply and divide the number by 100:
The fraction obtained can not be simplified because we do not have multiples of the numerator and denominator equal.
Answer:
1.07 repeating as a fraction is:
Answer: 123 crackers
Step-by-step explanation:
If 1/3 of the box contains sesame seed crackers, then, 2/3 of the box contains whole wheat and cheese flavored crackers.
Total number of whole wheat and cheese flavored crackers = 53 + 29 = 82
Let x be the total number of crackers in the box, so we will have the equation
2/3 x= 82
x = 82 ÷ 2/3; we will get
X =82 x 3/2
X = 123 crackers
{y y=-7, -2, 3, 8}
{xx=-7, -2, -1,0, 1, 2, 3, 8}
{y y=-7, -2, -1, 0, 1, 2, 3, 8}
Answer:
Range is given by the second option: {}.
Step-by-step explanation:
Range is the set of possible values in a given function.
Here, the function is defined by the following ordered pairs:
The y values of the function are {}
Therefore, the range is given as {}.
So, the second option is correct.
Answer:
B: {y: y = –7, –2, 3, 8}
Step-by-step explanation:
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The range is the Y, and the Y is the second number in the ordered pairs.
Answer:
A) For the poster: length = 9 inches and width = 3 inches
B) For the banner: length = 10 inches and width = 2 inches
Step-by-step explanation:
A) The perimeter was given as 24 inches, so that;
P = 2 (l+w)
But, l = 3w, where w is the width. So that;
P = 2 (3w + w)
24 = 2 (4w)
24 = 8w
⇒ w = 3 inches
But, l = 3w = 3 × 3 = 9 inches
Therefore for the poster, length is 9 inches and width is 3 inches.
B) With the same value of perimeter, 24 inches:
p = 2 (l+w)
But, l = 5w, where w is the width. So that:
p = 2( 5w + w)
24 = 2 (6w)
24 = 12w
⇒ w = 2 inches
But, l = 5w = 5 × 2 = 10 inches
Therefore, for the banner, length is 10 inches and width is 2 inches.
"A poster is 3 times as long as it is wide"
This means that the length is three times larger than the width of the poster (which is in the shape of a rectangle).
"A banner is 5 times as long as it is wide"
This is exactly the same as the one for the poster, except the length of the banner is FIVE times larger than the width, instead of three.
"Both the banner and the poster have perimeter of 24 inches"
Both the banner and poster are rectangles. The formula for perimeter for rectangles is P = 2L + 2W (L = length, W = width).Perimeter of the Poster = 2L + 2WPerimeter of the Banner = 2L + 2WFor the poster, it was mentioned that the length is 3x larger than the width, so that must mean L = 3 * W = 3W. So therefore:Perimeter of the Poster = 2(3W) + 2W = 6W + 2W = 8W.For the banner, it was mentioned that the length is 5x larger than the width, so that must mean L = 5 * W = 5W. So therefore:Perimeter of the Banner = 2(5W) + 2W = 10W + 2W = 12W.So we found our perimeters, which are 8W for the poster and 12W for the banner. But the question also states that BOTH perimeters are 24 inches. So we must set 8W equal to 24 and 12W equal to 24.8W = 24W = 3 inches (For the poster)12W = 24W = 2 inches (For the banner)So we found our widths of both the poster AND the banner. Now we just need to find the lengths. But remember how I stated earlier that the length for the poster is 3W (L = 3W)? And for the banner, it's L = 5W? We can use that to find the lengths since we already know values for the widths.For the poster:L = 3W = 3(3) = 9 inchesFor the banner:L = 5W = 5(2) = 10 inchesSo the poster has a length of 9 inches and width of 3 inches, and the banner has a length of 10 inches and a width of 2 inches