Explanation:
As we all know that like disolves in like solvent.
Here both water and Ethanol are polar. Hence Ethanol soluble in water.
Moreover, both forms intermolecular hydrogen bonds. It enhances the solubility of ethanol.
Both water and Ethanol are called as associate liquids. Hence solubility is more.
Alcohols have higher boiling point than other hydrocarbons due to their polarity and from the fact that they form very strong intermolecular hydrogen bonding. This is due to the large difference in their electronegativity that forms between the oxygen and the hydrogen atom.
B. A 2 kg pot at 120°C
C. A 5kg pot at 25°C
D. A 2 kg pot at 25°C
The 2 kg pot at 25°C has the least thermal energy because it has both a smaller mass and a lower temperature than the other options.
The thermal energy of an object is related to both its mass and its temperature. In this case, we are considering iron pots of different masses and temperatures. Given the options, the 2 kg pot at 25°C would have the least thermal energy. This is because it has both a smaller mass and a lower temperature than all the other options listed.
The thermal energy is calculated by multiplying the mass, specific heat, and change in temperature. An object with a smaller mass and lower temperature would therefore have less thermal energy.
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Answer: D. A 2 kg pot at 25C.
Explanation:
Hello!
What is the mass of 2.50 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
Data:
Molar Mass of NaOH = 40 g/mol
Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.50*10²² molecules
Product of extremes equals product of means
Solving: Find the mass value now
40 g ----------------- 1 mol of NaOH
x g ------------- 0.042 mol of NaOH
Answer:
The mass is 1.68 grams
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Answer:
Explanation:
125 cm3 -> 0.125 L
M = no. mole / volume (L)
M = 0.25 / 0.125 = 2 M
Answer:
C. Electrons
Explanation:
3.44x10^23 divided by 6.02x10^23 equals 0.571 mol Cu.
m = mass of the block of iron = 25 g
Q = heat absorbed by the block of iron = 1200 J
ΔT = increase in the temperature of iron due to heat absorbed = ?
c = specific heat of block of iron = 0.450 J/(g C)
Heat absorbed by the block of iron is given as
Q = m c ΔT
inserting the values in the above formula
1200 = 25 (0.450) ΔT
1200 = (11.25) ΔT
ΔT = 1200/11.25
ΔT = 106.67 C