The total fencing material required to surround the playground and flower bedswill be 8a + 2l + 2w.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
The boundary of a park is shaped like a circle.
The park has a rectangular playground in the center and 2 square flower beds, one on each side of the playground.
The length of the playground is l and its width is w.
The length of each side of the flower beds is a.
The total fencing material required to surround the playground and flower bedswill be
P = 2(perimeter of square) + perimeter of rectangle
Then the perimeter of the square will be
⇒ 4a
Then the perimeter of the rectangle will be
⇒ 2(l + w)
Then we have
P = 2 × 4a + 2(l + w)
P = 8a + 2l + 2w
More about the geometry link is given below.
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Answer:
PQR reduction of ABC in the ratio 16/24=2/3
PR =x = AC*2/3 = 30*2/3=20
QR = y= BC*2/3 = 9*2/3=6
Step-by-step explanation:
Answer:
x=20cm
y=6cm
Step-by-step explanation:
We are told ΔABC and ΔPQr are similar. This means their corresponding sides are in ratios to one another.
That means the ratio of AB to PQ, is equal to the ratio of AC to PR, is equal to the ratio of BC to QR. Written mathematically, this is:
Find x/PR
Since we know the values of AB, PQ, and AC, we can use to find PR (x):
1.5=
1.5x=30
x=20
Find y/QR
Since we know the values of AB, PQ, and BC, we can use to find QR (y):
1.5=
1.5y=0
y=6
B 4 zebra fish, 7 neon tetras
C 6 zebra fish, 5 neon tetras
D 5 zebra fish, 6 neon tetras
Answer: C. 6 zebra fish, 5 neon tetras. Is $21.60
Step-by-step explanation:
1.85 • 6 = 11.10
2.10 • 5 = 10.50
11.10 + 10.50 = 21.60
$21.60
True
False