The length of a rectangle is 5 more than twice the width. if the perimeter of the rectangle is 76 meters, find the dimensions of the rectangle and choose the equation that represents the perimeter:1. 76=2w+5
2. 76=2w+2(2w+5)
3. 76=w+2w+5
4. 76=2w+(2w+5)

Answers

Answer 1
Answer:

Answer:

Dimensions: 11 meters by 27 meters

2. 76=2w+2(2w+5)

Step-by-step explanation:

Finding Dimensions:

The perimeter of a rectangle can be written as 2l+2w where l is the length and w is the width. It is given that the length is 5 more than twice the length of width and the perimeter of the rectangle is 76 meters.

With this information we can write:

Length = 2w+5

2(2w+5)+2w = 76 (perimeter of the rectangle)

4w+10+2w=76

6w=66

w=11

Length = 2(11)+5

Length = 27

∴ The dimensions of the rectangle is 11 meters by 27 meters.

Perimeter

Since the length can be written as 2w+5, the equation that represents the perimeter of the rectangle is 76=2w+2(2w+5)


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Answers

Answer:

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Please give me brainly, somone in my family is a mathmatition...

Answer:

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Step-by-step explanation:

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Answers

so
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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers


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Answers

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Answer:

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Step-by-step explanation: