4a²(a³)/16b ( b²)
4a⁶/16b³
= a⁶/4b³
Answer:
this will work
Step-by-step explanation:
a class of 36 students needs to be separated into 4 groups for project. How many students will be in each group?
104.6 m^2
98.2 m^2
94.4 m^2
The answer is D. 94.4^2
((Hopefully I helped))
Does anyone know the answer to this problem
the answer is g=-4-10t
A. The sample is the percentage of students who ride the bus.
B. The sample might not be representative of the population because it only includes students who are attending an after-school activity.
C. The sample shows that exactly 38% of the students in the school ride the bus.
Soil A had greater growth because its data have a greater standard deviation.
Soil A had greater growth because its data have a greater mean.
Soil B had greater growth because its data have a greater interquartile range.
Soil B had greater growth because its data have a greater median.
Answer:
Step-by-step explanation:
Given is a table about plants growth in soil A and B.
Let us find mean and median.
Soil A
Mean: 4.17
Median: 3.9
Mode: 3.5
Minimum: 3.1
Maximum: 6
Range: 2.9
Count: 10
Sum: 41.7
Soil B
Mean: 4.28
Median: 4.25
Mode: 3.9
Minimum: 2.9
Maximum: 5.5
Range: 2.6
Count: 10
Sum: 42.8
Soil B shows a better growth since both mean and median are greater.
it Might be D. Soil B had greater growth because its data have a greater median.