10 times the square of a nonzero number is equal to 90 times the number. whats the number?

Answers

Answer 1

Answer: 9 because 10 times 9 is 90 and if you divide 90 by 10 you get 9

Answer 2

Answer: 10n^2 = 90n
n^2 = 9n
n = 9

Hope this helps with your question.

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Juan has scores of 85, 83, and 93 on three mathtests. What is Juan’s average test score on these
math tests?

Answers

Final answer:

To calculate Juan's average math test score, add all the scores together (85, 83, and 93) and then divide by the total number of tests, which is 3. The average score is 87.

Explanation:

The question given is a mathematics problem related to calculating an average. In particular, it is about finding the average test score of Juan's math tests. To find the average of a set of numbers, you add up all the numbers and then divide by the quantity of numbers. In this case, we add the test scores 85, 83, and 93 which gives us a total of 261. Since there are 3 tests, we divide this total by 3. So, Juan's average test score is 261 divided by 3, which equals 87.

Learn more about average here:

brainly.com/question/27193544

#SPJ12

Answer:

80.5

Step-by-step explanation:

to find average you need to first added all your number then divide by how much numbers you added

What conversions need to be performed to find the number of gtts in 20 ml

Answers

It would be from milliliters to gtts which means drops. From a 1 mL is equivalent to 20 drops while 1 drop is equivalent to 0.05 mL. If so, I calculated the given numbers of the problem and found the conclusion. The answer for it wold be 20 mL is equivalent to 400 gtts(drops).

Answer:

Hence number of gtts in 20 ml is 400gtts.

Step-by-step explanation:

"gtts means number of drops of water".

we know that 1 ml =20 gtts

Here we are asked to find the number of gtts in 20ml.

as 1 ml=20 gtts

⇒20 ml=20×20 gtts

⇒20ml=400 gtts.

Hence number of gtts in 20 ml is 400gtts.

Jonathan has been on a diet since January 2013. So far, he has been losing weight at a steady rate. Bases on monthly weigh-ins, his weight, w, can be modeled by the function w=-3m+205 where m is the number of months after January 2013.a) How much did Jonathan weight at the start of the diet?

b) How much weight has Jonathan been losing each month?

c) How many months did it take Jonathan to lose 45 pounds?

Answers

$a)\ \ \ w(m)=-3m+205\n\nm=0\ \ \ - at\ the\ start\ of\ the\ diet\n \nw(0)=-3\cdot0+205=205\n \nAns.\ weigh\ at\ the\ start\ of\ the\ diet\ is\ 205\ pounds\n \nb)\ \ \ w(m+1)=-3(m+1)+2015=-3m-3+205=-3m+202\n \nw(m+1)-w(m)=-3m+202-(-3m+205)=\n \n=-3m+202+3m-205=-3\n \nAns.\ Jonathan\ has\ each\ month\ 3\ been\ losing \n \n w(m)=205-45=160\ \ \ \Rightarrow\ \ \ -3m+205=160\ \ \ \Rightarrow\ \ \-3m=-45\n \nm=15\n \nAns.\ 15\ month$

What are the constraints of using transportable tablespaces? (Choose two.) A) The source and target character sets must match. B) The source and target database versions must match. C) The source and target platforms must match. D) The source and target time zone versions must match.

Answers

Answer:

The answer is B

Step-by-step explanation:

I took the assignment

Which equation is an identity?A. 7m – 2 = 8m + 4 – m

B. 8y + 9 = 8y – 3

C. 11 – (2v + 3) = –2v – 8

D. 5w + 8 – w = 6w – 2(w – 4)

Answers

An identity is obtained when you substitute any value of x to an equation, both sides will give out the same answer. A trial-and-error method is best used for questions like these. The method is shown below:

Let: 1 = m = y = v = w

A. 7m – 2 = 8m + 4 – m

7(1) – 2 = 8(1) + 4 – (1)
5 =/= 11

B. 8y + 9 = 8y – 3

8(1) + 9 = 8(1) - 3
17 =/= 5

C. 11 – (2v + 3) = –2v – 8

11 - (2(1) + 3) = -2(1) - 8
6 =/= -10

D. 5w + 8 – w = 6w – 2(w – 4)

5(1) + 8 -1 = 6(1) - 2(1 - 4)
12 = 12

Therefore, the choice D is the identity.

Complete the comparison: 3 + 7 > ?
A. 8+2
B. 10- 2
C. 7+3
D.9+4

Answers

3+7>10-2
This is because this simplifies to;
10>8
Answer is B. 3+7>10-2

The Answer is D! Because > means that the number on the right hand side is more than the left just think of it as an arrow! —>

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