The resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm
From the question,
We are to determine the resistivity of the wire
Resistivity can be calculated from the formula
Where is the resistivity of the wire
R is the resistance
A is the cross-sectional area
and is the length of the wire
From the given information,
R = 0.757 ohm (Ω)
A = 3.50 × 10⁻⁶ m²
= 25.0 m
Putting the parameters into the formula, we get
Hence, the resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm
Learn more on Calculating Resistivity here: brainly.com/question/5595373
B. molecule
C. compound
D. pure substance
Answer:
The answer is D. pure substance.
Explanation:
A pure substance is a particular class of homogeneous matter whose composition is fixed and chemically defined, that is, it has a stable chemical composition since it is a matter that remains chemically unaltered in its different states of aggregation, endowed with properties singular and characteristic. A pure substance is composed of entities such as molecules, formular units and atoms.
Answer : The maximum concentration of silver ion is
Solution : Given,
for AgBr =
Concentration of NaBr solution = 0.1 m
The equilibrium reaction for NaBr solution is,
The concentration of NaBr solution is 0.1 m that means,
The equilibrium reaction for AgBr is,
At equilibrium s s
The expression for solubility product constant for AgBr is,
The concentration of = s
The concentration of = 0.1 + s
Now put all the given values in expression, we get
By rearranging the terms, we get the value of 's'
Therefore, the maximum concentration of silver ion is .
B. graph positive slope
C. Graph positive area
D. Graph negative area
Answer:
B. graph positive slope
Explanation:
got it right
Answer:
0.87
Explanation:
Given :
Mass of bottle = 29.2 g
Mass when filled with diesel = 116.2 g
Mass when filled with water = 129.2 g
The mass of water = (Mass when filled with water - mass of bottle)
Mass of water = 129.2 - 29.2 = 100 g
Mass of diesel = (Mass when filled with diesel - mass of bottle)
Mass of diesel = 116.2 - 29.2 = 87
Relative density of diesel = mass of diesel / mass of equal volume of water
Relative density = 87 / 100 = 0.87
Answer:
29.7m
Explanatio