The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the molecular formula of the compound, showing your work.

Answers

Answer 1

Answer: To find the molecular formula of the compound, we get the molar mass of empirical formula CH2o which is 30 g/mol. We divided the molecular mass of 90.087 g/mol by 30, we get 3. Hence, we multiply each element by 3, getting the molecular formula of C3H6O3.

Answer 2

Answer:

Answer:

molecular formula = C₃H₆O₃

Explanation:

The empirical formula is the simplest formula of a compound obtained by converting the moles of each atom to the simplest ratio.

In order to determine the molecular formula we will first calculate the empirical formula mass of compound.

Empirical formula mass = mass of C + 2 X mass of hydrogen + mass of O

Empirical formula mass = 12 + 2 +16 = 30

given molecular mass = 90.087

Let us divide the molecular mass by Empirical formula mass

ratio = 90.087 / 30 = 3 (approx)

Thus the molecular formula = 3 X empirical formula of compound

molecular formula = 3 (CH₂O)

molecular formula = C₃H₆O₃

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Which statement would be the most useful for deriving the ideal gas law? Volume is directly proportional to the number of moles. Volume is inversely proportional to the temperature. Pressure is directly proportional to the volume. Pressure is inversely proportional to the number of moles.

Answers

The answer is: Volume is directly proportional to the number of moles.

Given the ideal gas equation: PV = nRT

We can see that pressure (P) and volume (V) are on the left side of the equation, while the number of moles (n), the gas constant (R), and temperature (T) are on the right side.

If you increase/decrease the volume, this results in a direct increase/decrease of the number of moles, which proves the statement true. Volume is also directly proportional to temperature. Pressure is inversely proportional to volume, and directly proportional to the number of moles.

Answer:

Explanation:

hydrogen is found primarily as two isotopes in nature: (1.0078u) and (2.0140u). Caluclate the percentage abundance of each isotope based on hydrogens average atomic mass

Answers

hydrogens average atomic mass = 1,01u

x = isotope about mass (1.0078u)
y = isotope about mass (2.0140u)

x + y = 100%
so:
x = 100% - y

$hydrogens ~average~atomic~mass=((1.0078\cdot x)+(2.0140\cdot y))/(100)\n 1.01=((1.0078\cdot (100-y))+(2.0140y))/(100)||\cdot 100\n 101=100.78-1.0078y+2.0140\n 101-100.78=1.0062y\n 0,22=1.0062y||:1.0062\n 0.219\%=y\n\n x=100\%-y\n x=100\%-0.219\%\n x=99.781\%\n\n$

answer:
$x=99.781\%\n y=0.219\%$

To break a chemical bond, energy must be(1) absorbed (2) destroyed (3) produced (4) released

Answers

Answer: 1) absorbed

Explanation:

As a chemical bond is formed either by transfer of electrons or sharing of electrons, in order to break the forces of attraction among atoms, energy must be absorbed.

Energy is produced or released when a chemical bond is formed.

Energy is never destroyed, it converts from one form to another.

To break a chemical bond, energy must be $\boxed{\left( 1 \right){\text{ absorbed}}}$ .

Further explanation:

The attraction existing between atoms and molecules that facilitate the formation of various chemical compounds is termed as a chemical bond. It is formed either due to electron transference or by electron sharing between the bonded atoms. The chemical bond formed as a result of electron transfer from one atom to another is known as an ionic bond. The bond formed by the mutual sharing of electrons is called a covalent bond.

Endothermic process

The basic meaning of “endo” is “in”. These processes need energy from the surroundings, generally in the form of heat. Photosynthesis, evaporation of water, sublimation of dry ice, and melting of ice are some of the examples of endothermic processes.

Exothermic process

The general meaning of “exo” is “out”. These processes release energy from the system to the surroundings in the form of heat. Combustion of fuels, thermite reactions, nuclear reactions, and neutralization reactions are some examples of exothermic processes.

Since bond breaking is an endothermic reaction, energy must be supplied or absorbed from the surroundings to the system. Therefore, option (1) is the correct answer.

Learn more:

Which of these is an extensive property? brainly.com/question/1398514
Which of the phase changes is an exothermic change? brainly.com/question/1875234

Answer details:

Grade: High School

Chapter: Chemical reactions

Subject: Chemistry

Keywords: chemical bond, ionic bond, covalent bond, exothermic, endothermic, in, out, heat, photosynthesis, melting of ice, thermite reactions, neutralization reactions.

What are the five branches of Earth Science?

Answers

Answer:

The following are the give branches of earth science

a) geology

b) oceanography

c) meteorology and climatology

d) environmental science

e) astronomy

Explanation:

a) geology: The study of earth as solid entity.

b) oceanography: study of oceans

c) meteorology and climatology: it deals with the study of atmosphere, the weather conditions, hurricanes etc, humidity, rainfall, etc.

d) environmental science: it deals with the study of environment, the impact of anthropogenic activities on environment.

e) astronomy: it is the study of outer space and the physical bodies beyond our planet, like study of moon etc.

Final answer:

Earth Science encompasses five main branches: Geology, Meteorology, Hydrology, Astronomy, and Environmental Science. Each one focuses on a specific aspect of the Earth's system and the understanding of how they interact and affect each other.

Explanation:

The Earth Science is a broad field that explores the interrelationships between physical and biological components of the Earth. It can be subdivided into five main branches:

Geology: the study of solid Earth and the processes that have shaped it over time.
Meteorology: the study of the Earth’s atmosphere, weather, and climate.
Hydrology: the study of water in all its forms (ice, water, vapor) on Earth's surface, underground and in the atmosphere.
Astronomy: the science of celestial bodies and the universe beyond Earth’s atmosphere.
Environmental Science: the study of the interactions between the physical, chemical, and biological components of the environment, including the impacts of humans on nature.

Learn more about Branches of Earth Science here:

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Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions. Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) S (s) (nonspontaneous)? Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq) (nonspontaneous)? 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq) (spontaneous?) Are these correct?

Answers

A electrochemical reaction is said to be spontaneous, if $E^(0) cell is positive.$

Answer 1:
Consider reaction: Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
   $S^(2-)/S // Ni^(2+)/Ni$

Hence, $E^(0)cell = E^(0) Ni^(2+/Ni) - E^(0) S/S^(2-)$
we know that, ${E^(0) Ni^(2+)/Ni = -0.25 v$
and ${E^(0) S/ S^(2-) = -0.47 v$

Therefore, $E^(0) cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^(0) cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)

The cell representation of above reaction is given by;
   $H_(2) / H^(+) // Pb^(2+) /Pb$

Hence, $E^(0)cell = E^(0) Pb/Pb^(2+) - E^(0) H_(2)/H^(+)$
we know that, ${E^(0) Pb^(2+)/Pb = -0.126 v$
and ${E^(0) H_(2)/ H^(+) = -0 v$

Therefore, $E^(0) cell$ = - 0.126 - 0 = -0.126 v

Since,   $E^(0) cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: 2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)

The cell representation of above reaction is given by;
   $Cr/Cr^(2+) // Ag^(+)/Ag$

Hence, $E^(0)cell = E^(0) Ag^(+)/Ag - E^(0) Cr/Cr^(2+)$
we know that, ${E^(0) Ag^(+)/Ag = -0.22 v$
and ${E^(0) Cr/ Cr^(2+) = -0.913 v$

Therefore, $E^(0) cell$ = - 0.22 - (-0.913) = 0.693 v

Since,   $E^(0) cell$ is positive, hence cell reaction is spontaneous

Answer: $Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)$ : non spontaneous

$Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)$ : non spontaneous

$2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)$ : spontaneous

Explanation:

a) $Ni^(2+)(aq)+S^(2-)(aq)\rightarrow Ni(s)+S(s)$

Here S undergoes oxidation by loss of electrons, thus act as anode. Ni undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Ni^(2+)/Ni])=-0.25V$

$E^0_([S^(2-)/S])=0.407VV$

$E^0=E^0_([Ni^(2+)/Ni])- E^0_([S^(2-)/S])$

$E^0=-0.25-(0.407V)-0.657V$

As value of $E^0$ is negative, the reaction is non spontaneous.

b) $Pb^(2+)(aq)+H_2(g)\rightarrow Pb(s)+2H^+(aq)$

Here Hydrogen undergoes oxidation by loss of electrons, thus act as anode. Pb undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Pb^(2+)/Pb])=-0.13$

$E^0_([H^(+)/H_2])=0V$

$E^0=E^0_([Pb^(2+)/Pb])- E^0_([H^(+)/H_2])$

$E^0=-0.13-(0V)=-0.13V$

As value of $E^0$ is negative, the reaction is non spontaneous.

c) $2Ag^(+)(aq)+Cr(s)\rightarrow 2Ag(s)+Cr^(2+)(aq)$

Here Cr undergoes oxidation by loss of electrons, thus act as anode. Ag undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_(cathode)- E^0_(anode)$

Where both $E^0$ are standard reduction potentials.

$E^0_([Ag^(+)/Ag])=+0.80V$

$E^0_([Cr^(2+)/Cr])=-0.913V$

$E^0=E^0_([Ag^(+)/Ag])- E^0_([Cr^(2+)/Cr])$

$E^0=+0.80-(-0.913V)=1.713V$

As value of $E^0$ is positive, the reaction is spontaneous.

How could you safely determine if a base is stronger than an acid?

Answers

Combine the two solutions. If the resulting salt is basic, you know the base was stronger. If you end up with an acidic salt, the acid was stronger.

Answer:

B) Use a conductivity apparatus

Explanation:

I got it right on Plato. Strong acids and strong bases will conduct more than weak acids and weak bases, so you can tell if one is stronger than the other by seeing which one conducts more.

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