An electron traveling with a speed of 2.50 × 10^6 meters per second collides with a photonhaving a frequency of 1.00 × 10^16 hertz. After the collision, the photon has 3.18 × 10^−18 joule of
energy.
Calculate the original kinetic energy of the electron. [Show all work, including the equation and
substitution with units.]
Answers
Answer;
K.E =2.85 × 10⁻¹⁸ Joules.
Explanation;
- Kinetic energy is the energy that keeps an object or a body in motion.
- Kinetic energy is given by the formula 1/2 mv², where m is the mass of the particle or body in motion, and v is the velocity.
K.E = 1/2 mv²
Mass of an electron = 9.11 × 10⁻³¹ Kg, velocity of the electron =2.5×10⁶ m/s
Thus, K.E = 1/2 (9.11 × 10⁻³¹ Kg) (2.5 × 10⁶ m/s)²
= 2.85 × 10⁻¹⁸ Joules.
The original kinetic energy of this electron is equal to 2.85 × 10⁻¹⁸ Joules.
Given the following data:
- Velocity of an electron =2.5 × 10⁶ m/s.
- Frequency = 1.00 × 10¹⁶ hertz.
- Photon energy = 3.18 × 10⁻¹⁸ Joules.
Scientific data:
- Mass of an electron = 9.11 × 10⁻³¹ Kg.
How to calculate kinetic energy?
Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
Where:
- K.E is the kinetic energy.
- M is the mass.
- V is the velocity.
Substituting the given parameters into the formula, we have;
K.E = 1/2 × 9.11 × 10⁻³¹ × (2.5 × 10⁶ m/s)²
K.E = 2.85 × 10⁻¹⁸ Joules.
Read more on kinetic energy here: brainly.com/question/1242059
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