Which statement best describes the kinetic theory of matter? Question 7 options: A. Matter is made up of particles that are in constant motion and have energy B. Matter is made up of particles that seldom move and do not possess energy C. Matter is made up of electrons that are in constant motion and have energy D. Matter is made up of particles that vibrate but do not possess energy E. Matter is made up of particles that seldom move and do possess energy
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Related Questions
View the image below and answer the question.The illustration above is an example of which of Newton's Laws?aUniversal Law of GravitationbNewton's Second LawcNewton's First LawdNewton's Third Law
Sebanyak 0,2 mol gas ideal berada dalam wadah yang volumenya 10 liter dan tekanan 1 atm . berapakah suhu gas tersebut
Juanita, en medio de la cuarentena tuvo que salir de su casa por algunos artículos que necesitaba; utilizó su tapabocas y guantes, salió corriendo con velocidad de 3m/s a comprar, 3 kilogramos de arroz, dos litros de leche y 5 tapabocas. Para completar el total de las cosas, primero debe ir al supermercado que esta ubicado a 50 metros, en dirección 30 grados con respecto a la horizontal partiendo desde su casa, y de allí, salir para la droguería que se encuentra ubicada a 70 metros, dirección 150 grados desde el supermercado geográficamente con respecto a la horizontal. 1. Clasifique las cantidades escalares y las cantidades vectoriales del problema
A solid wood door (???? = 1 3 ????(width) 2 ) 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 44.0 kg. Initially open and at rest, the door is struck at its center by a handful of sticky mud with mass 0.700 kg , traveling perpendicular to the door at 14.0 m/s just before impact. Find the final angular speed of the door in (rad/s).
with a0 and g are positive. Find the y-components of the velocity and acceleration of the rocket as a function of time. Graph ay vs t for 0 < t < t0.
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-- We know that the y-component of acceleration is the derivative of the
y-component of velocity.
-- We know that the y-component of velocity is the derivative of the
y-component of position.
-- We're given the y-component of position as a function of time.
So, finding the velocity and acceleration is simply a matter of differentiating
the position function ... twice.
Now, the position function may look big and ugly in the picture. But with the
exception of 't' , everything else in the formula is constants, so we don't even
need any fancy processes of differentiation. The toughest part of this is going
to be trying to write it out, given the text-formatting capabilities of the wonderful
envelope-pushing website we're working on here.
From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶
First derivative . . . y' (t) = (a₀ - g) t - 6 (a₀ / 30t₀⁴ ) t⁵ = (a₀ - g) t - (a₀ / 5t₀⁴ ) t⁵
There's your velocity . . . /\ .
Second derivative . . . y'' (t) = (a₀ - g) - 5 (a₀ / 5t₀⁴ ) t⁴ = (a₀ - g) - (a₀ /t₀⁴ ) t⁴
and there's your acceleration . . . /\ .
That's the one you're supposed to graph.
a₀ is the acceleration due to the model rocket engine thrust
combined with the mass of the model rocket
'g' is the acceleration of gravity ... 9.8 m/s² or 32.2 ft/sec²
t₀ is how long the model rocket engine burns
Pick, or look up, some reasonable figures for a₀ and t₀
and you're in business.
The big name in model rocketry is Estes. Their website will give you
all the real numbers for thrust and burn-time of their engines, if you
want to follow it that far.
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that nobody ever knew about before. When that happens, they
ADD the new one to the list of known dwarf planets, and then the
total number of dwarf planets on the list increases by 1 .
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your answer is C. 94 percent
i just took the test
B.The pressure of the water decreases.
C.The flow rate of the water decreases.
D.The density of the water increases.
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The flow rate of the water decreases as the cross section is decreases. So, the correct option is C.
What is Bernoulli's equation?
Bernoulli’s principle states that the total mechanical energy of a moving fluid, which includes the gravitational potential energy of height, the energy associated with fluid pressure, and the kinetic energy of fluid motion, remains constant.
The formula for Bernoulli’s principle is given as follows:
From the equation of continuity for incompressible fluids which is Bernoulli's equation
a v = constant
where, a is the area and v is the velocity.
Pressure is inversely proportional to the velocity.
From the image we can see that area of cross-section at A is greater than at B,
thus,
which means velocity of water will increase at B and water pressure will decrease.
Hence, the correct option is C, i.e. the flow rate of water decreases.
Learn more about Bernoulli's equation, here:
#SPJ2
C. The flow rate of the water decreases
b. High Renaissance
c. Late Renaissance
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Answer:
The correct answer is option B, High Renaissance
Explanation:
The high renaissance period is the first half of the 16th century which marked its beginning from 1490s and ended by late 15th century. Some of the best known artist of this period were Michelangelo, Raphael, Bramante, Leonardo da Vinci etc. The period of existence of these artist was
a) Leobardo Da Vinci - 1452-1519
b) Michelangelo - 1475-1564
c) Raphael – 1483 -1520
Answer:
The correct answer is option B, High Renaissance
Explanation:
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the diagonal of the car, at 5m/s, that speed is relative to the floor of the car.
The reason I have to assume that is because I think it makes the problem
easier. I could be wrong. And it's still troubling, because 5 m/s is a hefty
11.18 mph, which is a pretty energetic walk. (In fact, it's a 5min 22sec mile,
which I for one never accomplished, even when I was running.) But so be it.
-- The length of the car's diagonal is √(3² + 15²) = √(9 + 225) = √334
-- The angle of his walk along the diagonal is the angle whose tangent is 3/15.
-- His velocity consists of the components [ 5 cos(angle) east ] and
[ 5 sin(angle) north ].
That's [ 5 x 15/√334 east ] and [ 5 x 3/√334 ] north .
The train's motion adds to the easterly component of his velocity,
and that becomes [ (2.5) + (5 x 15/√334) ] . The train's motion has
no effect on the northerly component of his velocity.
So now we're ready to put the components together and find his velocity
relative to the tracks. I think it'll be easier to go ahead and get the numerical
value of each component, and then combine them.
Easterly component: (2.5) + (5 x 15/√334) = 6.6038 m/s
Northerly component: 5 x 3/√334 = 0.8208 m/s
Just before finding the magnitude, we note that the direction of his velocity
is (the angle whose tangent is 0.8208/6.6038) north of east. That's about
7.085 degrees north of east ...the compass bearing of 82.92 degrees.
Now for the magnitude. It's the square root of the sum of the squares of
the easterly component and the northerly component.
√ (6.6038² + 0.8208²) = √44.2841 = 6.655 m/s
(All numbers are rounded.)
That's my story, and I'm sticking with it.