The resultant of the force is 100 Newton in the direction of 36.90°.
A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
Let's learn vector addition and subtraction after first learning what a vector is. The simple arithmetic principles are not followed when adding or subtracting vector values. The addition and subtraction of vectors are conducted in accordance with a unique set of guidelines.
Given:
Force F₁ = 60 Newton east
Force F₂ = 80 Newton north
The resultant of the force is = √((60)² + (80)²) Newton = 100 Newton.
The direction of the force is = tan⁻¹(60/80) = 36.90°
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Answer:
potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Explanation:
Answer:
C. 8.56cm
Explanation:
Since we are to get the difference of cord length in centimeter, there fore we will have to convert the one yard and one metre length of wires to centimeters.
For 1m length of cord
1m = 100cm
For 1yard length of cord
1yard = 91.44cm
Difference in cord length = 100cm - 91.44cm
= 8.56cm
Answer:
C.
Explanation:
A meter is 8.56 centimeters longer than a yard. Something to keep in mind is that a meter is about 10% longer than a yard.
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The final velocity of car 1 is -0.36 m/s to the left, and the final velocity of car 2 is 6.69 m/s to the right.
The conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system remains constant if no external forces act on the system. In other words, the total momentum of a system before a collision or interaction is equal to the total momentum of the system after the collision or interaction, as long as there are no external forces acting on the system.
Mathematically, we can express the conservation of momentum as follows:
P_initial = P_final
Where:
P_initial is the total momentum of the system before the interaction or collision
P_final is the total momentum of the system after the interaction or collision
Momentum is a vector quantity, which means it has both magnitude and direction. Therefore, the conservation of momentum applies separately in each direction. For example, if two objects collide and move in different directions after the collision, the momentum of one object in the positive direction will be equal and opposite to the momentum of the other object in the negative direction, so the total momentum of the system is conserved.
The conservation of momentum is an important principle in many areas of physics, such as mechanics, electromagnetism, and quantum mechanics. It is used to analyze collisions, explosions, rocket propulsion, and other physical phenomena involving the transfer of momentum.
Here in the Question,
To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, since the collision is elastic. According to these laws, the total momentum and total kinetic energy before and after the collision must be equal. We can write this as:
Total initial momentum = Total final momentum
and
Total initial kinetic energy = Total final kinetic energy
Let's first find the initial momentum of the system:
P_initial = m1v1 + m2v2
= (0.75 kg)(8.5 m/s) + (0.65 kg)(-7.2 m/s) (since car 2 is moving to the left, its velocity is negative)
= 1.225 kg m/s to the right
According to the law of conservation of momentum, the total momentum of the system must be conserved after the collision. Therefore, the final momentum must also be 1.225 kg m/s to the right.
Let's now find the initial and final kinetic energies of the system:
KE_initial = (1/2)m1v1^2 + (1/2)m2v2^2
= (1/2)(0.75 kg)(8.5 m/s)^2 + (1/2)(0.65 kg)(-7.2 m/s)^2
= 26.228 J
According to the law of conservation of kinetic energy, the total kinetic energy of the system must also be conserved after the collision. Therefore, the final kinetic energy must also be 26.228 J.
Let's now find the final velocities of the two cars. We can use the momentum conservation equation to set up a system of two equations (one for the conservation of momentum and one for the conservation of kinetic energy) with two unknowns (the final velocities of the two cars). Solving this system of equations, we get:
v1f = (m1-m2)/(m1+m2)v1 + 2m2/(m1+m2)v2
= (0.75 kg - 0.65 kg)/(0.75 kg + 0.65 kg)8.5 m/s + 20.65 kg/(0.75 kg + 0.65 kg)(-7.2 m/s)
= -0.36 m/s to the left
v2f = 2*m1/(m1+m2)*v1 - (m1-m2)/(m1+m2)v2
= 20.75 kg/(0.75 kg + 0.65 kg)8.5 m/s - (0.75 kg - 0.65 kg)/(0.75 kg + 0.65 kg)(-7.2 m/s)
= 6.69 m/s to the right
Therefore, the final velocity of car 1 is -0.36 m/s to the left, and the final velocity of car 2 is 6.69 m/s to the right.
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Answer:
Option A
Explanation:
Newton's third law : They have equal magnitude but directed in opposite direction.