The correct answer to the question will be that the electric force between them will be decreased.
EXPLANATION:
Let us consider the charge contained by A and B are denoted as Q and Q' respectively.
Let R is the separation distance between them.
As per Coulomb's law in electrostatics, the force of attraction or repulsion between the two charge bodies A and B will be -
Coulombic force F =
Here, is the permittivity of the medium in which the charges are present.
From above, we see that electric force is inversely proportional to the square of separation distance between them.
Mathematically it can be written:
As per the question, the distance between A and B is increased.
Hence, the electric force between A and B will be decreased.
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?
long and how
often have to do with exposure to chemicals?
Well how much, how long, and how often
For example how much is like how much a object is left in a small room with chemicals
How long is the time
how often is how much the same cycle is done repeatedly
virtual
the same in size
smaller in size
An object that is farther from a converging lens than its focal point always has an image that is virtual. Option (b) is correct.
An optical lens that is thicker in the center and narrower at the corners is referred to as a converging lens, also known as a convex lens. Because it causes parallel light rays to converge or come together at a certain location known as the focal point, it is referred to as a "converging" lens.
The image created is virtual, meaning that it appears to be on the same side of the lens as the object when an object is placed farther away from a converging lens than its focal point. The virtual image is also enlarged, making it look bigger than the actual object. Additionally, the image is upright, not inverted.
Hence, an object that is farther from a converging lens than its focal point always has an image that is virtual. Option (b) is correct.
To learn more about converging lens, here:
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