the time t required to drive a certain distance varies inversely with the speed, r. if it takes 4 hours to drive the distance at 40 miles per hour, how long will it take to drive the same distance at 55 miles per hour? a. about 2.91 hours b. about 160.00 c. 22.00 hours d. about 5.50 hours

Answers

Answer 1
Answer: Hello,

Answer A

d :the distance in miles
t: the time in hours
v: the speed in miles/hours (vistesse)


d=v*t
==>d=40*4=160(mi)

d=55*x=160==>x=160/55=2.909090... (mi/(mi/h)=h)≈2.91(hours)
Answer 2
Answer:

The time it would take to drive the same distance at 55 miles per hour is 2.91 hours.

What is the time needed to drive the same distance?

If time varies inversely with speed, as time increases, speed decreases. This means that the faster one travels, the lower the time it would take to reach the destination.

The equation that can be used to represent inverse relation is:

t = k / r

Where k is the constant of proportionality

4 = k/40

k = 160

160 / 55 = 2.91 hours

To learn more about inverse proportion, please check: brainly.com/question/25748643

#SPJ5


Related Questions

Decide whether the following statement makes sense​ (or is clearly​ true) or does not make sense​ (or is clearly​ false). Explain your reasoning.If interest rates stay at 4​% APR and I continue to make my monthly ​$50 deposits into my retirement​ plan, I should have at least ​$30 comma 000 saved when I retire in 25 years.The statement ___________ because I will have ​$ ___________ nothing in my retirement account when I retire in 25 years.​(Round to the nearest cent as​ needed.)
What is
Express the product in simplest form 8/2x+8 * x^2-16/4
40.54-29.63Math problem Hey
-8W + 5 = -43I need help asap

Calculate the following limit:

Answers

\lim_(x\to\infty)\frac{\sqrt x}{\sqrt{x+√(x+\sqrt x)}}=\n\lim_(x\to\infty)\frac{(\sqrt x)/(\sqrt x)}{\frac{\sqrt{x+√(x+\sqrt x)}}{\sqrt x}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{(x+√(x+\sqrt x))/(x)}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+(√(x+\sqrt x))/(x)}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+(√(x+\sqrt x))/(√(x^2))}}=\n
\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(x+\sqrt x)/(x^2)}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+(\sqrt x)/(√(x^4))}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+\sqrt{(x)/(x^4)}}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+\sqrt{(1)/(x^3)}}}}=\n=\frac{1}{\sqrt{1+\sqrt{0+√(0)}}}=\n
=(1)/(√(1+0))=\n=(1)/(√(1))=\n=(1)/(1)=\n1

Make it 0 on one side

x2 - 2x + = 4(x2-2x +1)-3

Answers

Answer:

-3x² +6x -1 = 0

Step-by-step explanation:

x2 - 2x + = 4(x2-2x +1)-3

x² - 2x = 4x²-8x +4 - 3

x²-4x²-2x+8x = 4-3

-3x² +6x = 1

-3x² +6x -1 = 0

Solutions for 12 – x2 = 0?

Answers

Answer:   x =  ±  2 √3 ;  or,  write as:   x  =   ± 3.464  .
__________________________________________________
Given:  12 – x² = 0 ; 

Multiply BOTH side by "-1" ;
__________________________________________________
-1 (12 – x² = 0) ;

to get:

-12 + x² = 0 ;

Rewrite as:

x²  - 12 = 0 ;

Add "12" to both sides; to get: 

x² = 12 

Take the square root of each side:

√(x²) = ±√(12)

x = ± √(12) 
_________________________________________________
√(12) = √(4) * √(3) = 2 √(3)

√(12) = 3.4641016151377546 ; round to:  3.464 .
____________________________________________________
x = ± √(12) ;
____________________________________________________
x =  ±  2 √3 ; or, write as:  x =  ± 3.464 .
____________________________________________________

Represents the following phraseall real numbers that are between - 8 and 3
Compound inequality

Answers

the compound inequality for real numbers between -8 and 3 is -8

Which of the following is a polynomial with roots 4, –2i, and 2i ?

Answers

(x - 4)(x + 2i)(x - 2i) = 0
x(x^2 + 4) - 4(x^2 + 4) = 0
x^3 + 4x - 4x^2 - 16 = 0
x^3 - 4x^2 + 4x - 16 = 0

Does a triangle with the lengths 12, 18, and 2 exist

Answers

Answer:

yes

Step-by-step explanation:

I got it right