MATHEMATICS HIGH SCHOOL

What is $12^(2)$

Answers

Answer 1

Answer:

Hello there!

This question is so super easy to me.

Explanation

↓↓↓↓↓

First you had to simplify it should be the correct answer.

$12^2$

$12*12$

$=144$

Answer⇒⇒⇒⇒⇒144

Hope this helps!

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Have a great day!

-Charlie

Answer 2

Answer: 12 squared is just 12 times 12 so its 144

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When h has the value 12 calculate 5h - 2

AC and BD are perpendiculare bisectors of each other find the perimeter of ABC 30

Answers

Answer:

36 is the answer i was counting middle line oft triangle abc and it was throwing me off

Step-by-step explanation:

Mr. Willett was taking 3 students on a hiking excursion. He had 2 2⁄3 pounds of trail mix to split between the students. How many pounds trail mix did each student get?

Answers

Answer:

4/3 each student

Step-by-step explanation:

2+ $(2)/(3)$ = $(8)/(3)$

if there are 3 students, we should split the total amount of trail mix by 3

$(8)/(3)$ ÷3=8/6= 4/3 each student

Hey, Whats The answer please explain your answer marking brainliest:D. Please Help Im tired..

Answers

Answer:

The answer is C

Step-by-step explanation:

-3+3 is 0

Answer:

Step-by-step explanation:

The distance between -3 and 0 can be calculated by the absolute value of the difference of the two numbers. -3-0 = -3. |-3| = 3

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each student can choose two electives. Which expression represents the probability that a student chooses an art elective and a history elective?

Answers

Answer:

$(^3C_1* ^4C_1)/(^(12)C_2)$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1* ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^(12)C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=(^3C_1* ^4C_1)/(^(12)C_2)$

Which is the required expression.

Answer: Hello!

we have:

3 art electives

4 history electives

5 computer electives

which adds to a total of 12.

If the selection is random, each elective has the same probability.

The probability of selecting an art electives is the quotient between the number of art electives and the total number of electives:

3/12

suppose that this event is true, now we need to see the probability of choosing also a history elective;

We do the same process as before, we have 4 history electives and, because we already selected 1 in the previous step, we have a total of 11 electives:

the probability now is 4/11.

Now we want to calculate the joint probability of bot events is equal to the product of their probabilities; this is:

p= (3/12)*(4/12) = (4*3)/(11*12) = 12/(11*12) = 1/11

But there is also the case where the selection is in the other order (first history and second art) so the probability is equal to

2*1/11 = 2/11

20
X + 60°
X=
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80