Which are all the solutions of 5sinθ-4=2sinθ-4, where 0≤θ≤2π

Answers

Answer 1

Answer: 5sinx-4 =2sinx-4
5sinx-2sinx= 4-4
3sinx=0
sinx=(0÷3)
sinx = 0
x = sin^-1 (0)
x= 0 degrees

And also x = (180- 0 ) = 180 degrees

so x; has 2 answers within the above given interval.

They are;
x= 0 degrees and x=180 degrees

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The number of girls at Sky High School is 60 greater than the number of boys. If there are 1250 students all together, how many girls are there all together?

Answers

$girls : x\nboys : y \n \n x= y+60 \nx+y=1250 \n\nsubstitution : \n \n y+60+y=1250 \n 2y=1250-60\n2y=1190 \ \ / :2 \n y= 595 \n \n x=595 +60=655 \n \nAnswer : \ there \ is \ 655 \ \ girls \ and \ 595 \ boys$

595 in boys and i think 655 in girls

What is the value of g[f(4)] for the functions f(x) = 3x-5 and g(x) = 2-x^2

Answers

Answer: -47

Work Shown

f(x) = 3x-5

f(4) = 3*4-5

f(4) = 12-5

f(4) = 7

We can then replace f(4) with 7 to go from g[ f(4) ] to g(7)

g(x) = 2 - x^2

g(7) = 2 - 7^2

g(7) = 2 - 49

g(7) = -47

A coach can hold 50 people. how many coaches would you need for 440 people

Answers

Final answer:

To transport 440 people, you would need 9 coaches.

Explanation:

To find out how many coaches you would need for 440 people, you need to divide the total number of people by the capacity of each coach.

Using the formula:

Number of coaches = Total number of people / Capacity of each coach

Plugging in the values, we have:

Number of coaches = 440 / 50 = 8.8

Since you cannot have a fraction of a coach, you would need to round up to the nearest whole number. Therefore, you would need 9 coaches for 440 people.

Learn more about Division here:

brainly.com/question/2273245

#SPJ11

Answer:

9 coaches

Step-by-step explanation:

440 ÷ 50 = 8.8

You need to round up to 9

In the xy-plane, triangular region R is bounded by the lines x=0, y=0, and 4x+3y=60. Which of the following points lie inside region R?a. (2, 18)
b. (5, 12)
c. (10, 7)
d. (12, 3)
e. (15, 2)

Answers

Convert the equation of the line to the slope-intercept form:
$4x+3y=60 \n3y=-4x+60 \ny=-(4)/(3)x+20$

All points which lie inside region R satisfy the system of inequalities:
$x\ \textgreater \ 0 \ny\ \textgreater \ 0 \ny\ \textless \ -(4)/(3)x+20$

You can see all coordinates in your choices are positive, so the first two inequalities are satisfied. We must check which points satisfy the third inequality.
Plug the values (x,y) into the inequality and check:
$(2,18) \n18 \ \textless \ -(4)/(3) * 2+20 \n18 \ \textless \ -(8)/(3)+20 \n18\ \textless \ -2(2)/(3)+20 \n18\ \textless \ 17 (1)/(3) \nfalse \n \n(5,12) \n12\ \textless \ -(4)/(3) * 5+20 \n12\ \textless \ -(20)/(3)+20 \n12\ \textless \ -6(2)/(3)+20 \n12\ \textless \ 13 (1)/(3) \ntrue$

$(10,7) \n7 \ \textless \ -(4)/(3) * 10+20 \n7\ \textless \ -(40)/(3)+20 \n7\ \textless \ -13 (1)/(3)+20 \n7\ \textless \ 6 (2)/(3) \nfalse \n \n(12,3) \n3\ \textless \ -(4)/(3) * 12+20 \n3\ \textless \ -(48)/(3)+20 \n3\ \textless \ -16+20 \n3\ \textless \ 4 \ntrue$

$(15,2) \n2 \ \textless \ -(4)/(3) * 15+20 \n2\ \textless \ -(60)/(3)+20 \n2\ \textless \ -20+20 \n2\ \textless \ 0 \nfalse$

The answer is B and D.

Find the greatest common factor (GCF) for 72, 36, and 24.

Answers

12

Working;
12 is a common factor for all the terms.

A box has sides of 10 cm, 8.2 cm, and 3.5 cm. What is its volume?

Answers

To find the volume of a rectangular prism, you simply need to multiply the length (in this case, 10) by the width (8.2) by the height (3.5). When we do this, we are left with this:

10 * 8.2 * 3.5 = 82 * 3.5 = 287

The volume of the box is 287 cubic centimeters.
Hope that helped! =)

10*3.5*8.2=287

You times all of them together to get the general volume of the box. You use the equation Base*Width*Height = General volume of a Cube.

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